#equivalent ballast of screws

12 messages · Page 1 of 1 (latest)

wraith lance
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Hey, so this is more a Statik / structural analysis problem, but I hope someone may still know or could lead the way elsewhere.

I want to proof that my structure can withstand a push of certain strength. Currently it does not, so the easiest way to fix this is to add weight to the baseplate. I was wondering how I would get the "weight" that a set of screws into a wooden floor below would work as

sterile rapidsBOT
#
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sterile rapidsBOT
wise prism
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when you mean the weight i assume you mean the moment that it would apply?

wraith lance
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yeah

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I asked somewhere else as well, maybe that wording / details helps to understand.

I am doing some Statik / structural analysis stuff rn, specifically I need to proof that my truss construct is safely standing even if pushed by a panicked mass trying to evacuate (you assume a push of 1kN at a height of 1m). My current setup obviously isn't heavy enough by itself, so I need additional weight on the baseplate.

Does anyone know how I can calculate the equivalent ballast that 8 5x50mm screws into the wooden floor below would get me?

In that chat we kinda came to the conclusion of "It's complicated..."
Like, if I had actual fittings and torqued bolts it'd be one thing, but into wood, when I don't even know the type of wood (it's a theatre stage floor), definitely way more complex

wise prism
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honestly moth maths involve modelling but real world applications are extremely complicated. Is your question simple curiosity or are you trying to make the resultant force exactly 0 or?

wraith lance
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We were only told to use additional weight in the lessons, and yes, the goal is to have the standing moment be bigger than the push moment.

I just know that at my local theatre they're more likely to screw it down than throw extra weight and got curious how that'd be calculated

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#

@wraith lance

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wraith lance
#

+close

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