#how do you figure out vertex i forgot

22 messages · Page 1 of 1 (latest)

glossy escarpBOT
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glossy escarpBOT
celest seal
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coordinate or value of vertex?

naive rover
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ye

celest seal
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coordinate by -b/2a, value by f(-b/2a)

naive rover
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??

celest seal
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you figue out vertex by expanding into form ax^2 + bx + c = 0
heres where its -b/2a

naive rover
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i promise it was much simpler

celest seal
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could you recall what your teacher did?
the standard way is this formula. i am nto sure what your teachr cooked

naive rover
celest seal
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that value is -b/2a

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you plug this in

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'b' and 'a' are from ax^2 + bx + c form

iron tusk
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For a quadratic function:

h = -b / 2a

Find the x-coordinate of the vertex using h.
Then substitute h into the function:

k = f(h)

The vertex is:

(h, k)

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My English doesn't good so it might be kinda of on grammar or meaning but the rest is correct

nimble glacier
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I have a question can you use po shen to get the x cordinate for vertex? Y might be different but we can find x axis?

iron tusk
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I don't know what “Po Shen” is, but if you have a quadratic equation(ax²+bx+c), for example x²-4x+3, you can always find the x-coordinate of the vertex using -b/2a
Like in this example, 2 is our x-value, and to find the y-coordinate, you have to substitute the x-value you found into the quadratic equation to get the y-value of the vertex. Like for that example(x²-4+3)
y(the y coordinate of vertex)=2²-4.2+3
y=-1
So the vertex is (2,-1) the fact is i don't know what is Po shen but if u say what s it I can try to help in fact im not English so nearly all the Terms is different in my country

iron tusk
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Oh u talking about
The sum of roots
which is X₁₊X₂=-b/a and with that u can find the x of the vertex by dividing 2
Like the x-coordinate of vertex is x=(X₁₊X₂)/2
And if u put the number u find to the quadratic equation (ax²+bx+c) u find the y of the vertex
F((X₁₊X₂)/2)=a((X₁₊X₂)/2)²+b((X₁₊X₂)/2)+c

iron tusk
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You can think of it as coming from the idea of a number line. To find the midpoint of a line, you pick the two end values, add them together, and divide by 2
And this is why we divided the sum of roots the half for the finding x of the vertex

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And by putting x of the vertex to quadratic equation we find the y of the vertex

glossy escarpBOT
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@naive rover

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