GED help

[vestal flume]

Hello everybody, i started doing ged last year...it was my first year doing school in english instead of afrikaans and i got miserable and unmotivated, i got a job and neglected my school work even more, i treid to study before and after work but nothing got through to me and now a yearbhas passed and i need to write exams...but i need help withsome equations and functions

[woeful hatch]

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[somber merlin]

What specifically with functions and equations do you need help with

[vestal flume]

Quadratic equations, (solving for x in solution sets)
And with functions i need basic help with the determining of what equations to use for certain functions and if for example they give me a function, how do i know what equation to use

Heres an example of what i struggled with, i know the answer now, its a mock test but i still dont know how to do it

[somber merlin]

So with quadratic equations, in the form of ax²+bc+c, there are various ways to solve for the variable.

First, you can factor it. Find two numbers that multiply to a*c, but also add to b (including the negative sign if there is one). Then, you'd write the factors with that. For example, with x²-3x+2, two numbers that multiply to -2 and add to -3 are -2 and -1. So, it becomes (x-2)(x-1).

Second, if the leading coefficient (the coefficient on the x² term) isn't 1, you can factor by grouping, which involves the same process for the first one, except you substitute those numbers (ex; -2x, -1x) into the original quadratic, rearrange if needed to get the ratios right, and then factor out the common term, and then group.

Third, you can complete the square. If you have, for example, x²+6x+12, you would subtract 12 from both sides, take half of 6, square it to get 3²=9, add that to both sides, then factor the new quadratic, and solve for x. So with that x²+6x+12, I'd have 1) x²+6x=-12, 2) x²+6x+9=-3, 3) (x+3)²=-3, 4) x+3=√(-3), and lastly 5) x=-3+√(-3).

And then if you must, you can use the quadratic formula

I'ma respond to the other part a bit later

[vestal flume]

Okay thank you so much!

[somber merlin]

Of course

Now, with the graph and the slope of the line, the formula is ∆y/∆x. It's kinda hard to put the expansion in text, so I suggest looking it up

[vestal flume]

Okay thank you for your help, ill go look it up

I think i remember it from my other curriculum i followed before ged

Is it like where you take the y values minus them and then put that over the x values

Like this?

[somber merlin]

Yessir

Just be consistent with your y2/y1 values and x2/x1 values

[woeful hatch]

@vestal flume

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[vestal flume]

Oki thank you for your help david

+close

[woeful hatch]

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