I assume such an approximation for huge $n$ can be made?
#Approximation
dusty badger
verbal prismBOT
Dhairya
misty warren
I assume such an approximation for huge $n$ can be made?
the limits are the same. if we delete "lim" from both sides, the difference between these two is at most $$\frac{nq\sqrt{3}}{4\pi \varepsilon_0} \sum_{k=0}^n \frac{1}{(n\sqrt{3})^3} = O(1/n) \to 0$$
so yeah
verbal prismBOT
\nothing
dusty badger
the limits are the same. if we delete "lim" from both sides, the difference betw...
ok.
hybrid yacht
icse