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floral falcon
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Imagine a tanker of height h which is empty initially is being filled with water, water coming out from an oil pipe at the rate of x unit volume/sec. Suppose, initially water is coming alone but oil also began to come from same pipe(mixed with water) such that its rate increases by x² unit volume/sec, then at what height will the amount of water and amount of oil in the tanker will become equal?

wraith tulipBOT
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neon radish
# floral falcon Imagine a tanker of height h which is empty initially is being filled with water...

The problem asks for the height at which this occurs. In a uniform tanker (like a cylinder or prism), the volume is equal to the base area (A) multiplied by the height (H).
If we assume the problem intends for the base area of the tanker to be 1 square unit (or if the rates were originally intended to represent units of height per second rather than volume), the exact height at which the amounts of water and oil become equal is 4 units of height.

floral falcon
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And the answer is h=50x/πr²

floral falcon
neon radish
humble bolt
neon radish
humble bolt
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Have you gone through the helper guidelines of the server?

neon radish
floral falcon
wraith tulipBOT
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@floral falcon

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floral falcon
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+close

wraith tulipBOT
# floral falcon +close
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wraith tulipBOT
# wraith tulip

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wraith tulipBOT
# wraith tulip

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