#can someone help me with square roots please

21 messages · Page 1 of 1 (latest)

stable flaxBOT
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stable flaxBOT
forest aurora
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well, if I asked you what the square root of 81 is, would you know what it is?

fathom fog
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Yeah, I can help. Is it simplifying, estimating, or solving with square roots?

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thats actually how most people feel about square roots at first 😭 what are you stuck on?

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okay, here an example if 9x9 is 81, what is the square root of 81? it's 9 because 9^2 is 81 so squareroot 81 is 9 (it's the opposite of exponentss)

fluid kernel
fluid kernel
fathom fog
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yeah cube toots are a bit trickier at first, but an easy way is to memorize some perfect cubes like 1, 8, 27, 64, 125. then you just match the number to the cube ro

forest aurora
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you rarely have to evaluate roots, usually you'll be able to use a calculator to do it for you

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but usually, if it's an irrational number, you'll just leave the radical and simplify it as much as possible

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so if your answer is $\sqrt{8}$ you'd just write $2\sqrt{2}$ instead of rounding it to 2.828...

dull cometBOT
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Helcovich Emire

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forest aurora
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but sometimes you will need to evaluate roots of large numbers

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the best thing to do is to factor it into a product of primes

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and then to find the nth root, anytime you see a prime number with exponent more than n, subtract n from it and put that factor raised to the first power out front.

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so if you're trying to find the $\sqrt[5]{8064}$, factor it to $\sqrt[5]{2^{7}\cdot3^{2}\cdot7}$ then since 2 is raised to power of 7, subtract 5 from it, and put a 2 out front so it'd be $2\sqrt[5]{252}$ after multiplying all the leftover factors back together

dull cometBOT
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Helcovich Emire

1427447905005867008.png
stable flaxBOT
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@fluid kernel

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@forest aurora @fathom fog The user still needs help with this help request.