#Can someone give me the steps to solve these?

24 messages · Page 1 of 1 (latest)

finite umbra
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I would like to know the steps to this radical equation and how to find the zeros of a quadratic function. This is for my test 2 review for college algebra

tight ospreyBOT
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somber glen
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For the first one, all ya gotta do is solve for the values of x.

Subtract 4, square both sides, set equation equal to 0, then factor, then solve for x, and test for extraneous solutions by plugging in your solutions x in the original equation

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For the second one, set it equal to 0, factor out GCF, set each factor equal to 0, solve for possible x-values

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And boom ya get your answers

finite umbra
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How do you factor 3 with 14?

fervent cosmos
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You cant just remove the 4

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You need to write x-4 on the other side instead of x

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And then square both sides

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And when they said equate to zero, basically put all the terms to one side

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Would it help if I send a pic of the steps?

finite umbra
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Yes, sorry

fervent cosmos
finite umbra
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Thank you

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Do you guys know of good ways to find gcf?

somber glen
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It is the case here that no solution is extraneous, but not always

tired cove
# finite umbra Do you guys know of good ways to find gcf?

You mean GCD?
The method I was taught was prime factorization method. I will illustrate this method by an example

12 and 18
We first prime factorize
12 = 2^2 * 3^1
18 = 2^1 * 3^2
To find GCD, pick the least amount of primes in the two numbers
we have 2^1 and 2^2. So least is 2^1
we have 3^1 and 3^2. least is 3^1
Now multiply them: 2 * 3 = 6
so 6 is the GCD of the numbers

There si another method called Euclidean Algorithm, but I don't have enough knowledge of it. You can search that

finite umbra
fervent cosmos
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The gcf here 3

fervent cosmos
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3x

tight ospreyBOT
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@finite umbra

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