#partial derivatives f(x,y)= 5x^3 -y^2 +3x*y

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dim star
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f(x,y)= 5x^3 -y^2 +3x*y
What is f(x,y).
What is the rule of this #1015578016606343218

spare gyroBOT
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spare gyroBOT
sage dove
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Do you mean the partial derivative with respect to y ?

dim star
sage dove
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The answer is already given here

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Do you not understand how they arrived at it ?

dim star
dim star
sage dove
rain sunBOT
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Exotic_rotor

sage dove
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And I’m assuming $f_{y}(x,y)$ as well

rain sunBOT
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Exotic_rotor

sage dove
# dim star How

Oh nvm I misread the question, I thought you had to calculate the partial derivatives for the function in the image

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f(x,y)=5x^3-y^2+3xy, to calculate t he partial derivative with respect to x you must fix your variable y, so your function is a function of x, your see y as a constant, then calculate its derivative as a function of x

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The only thing you need to know is how to calculate a derivative

dim star
sage dove
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Can you calculate the derivative of $g(x)=5x^3-y^2+3xy$ ?

rain sunBOT
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Exotic_rotor

sage dove
dim star
sage dove
dim star
dim star
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@sage dove do i get it

dim star
umbral jay
snow idol
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when u partial derivative on X

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everything else is a const

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so

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Y^2

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is basicaly like 5^2

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became 0 after the first derivative

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so like

dim star
snow idol
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yeah

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imagine that Y becomes a basic integer

dim star
snow idol
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well

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as before

dim star
snow idol
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imagine y is like

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5

dim star
dim star
snow idol
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$$ f(x,y) = 3xy $$ then $$ \partial_x f(x,y) = 3*y $$

rain sunBOT
dim star
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Everything's is good

snow idol
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but for ur whole case :
$$ \partial_x f(x,y)=10x+3y $$

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bot???

rain sunBOT
dim star
snow idol
rain sunBOT
dim star
snow idol
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okkah

dim star
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@snow idol did I do it right or worng

umbral jay
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But yeah

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5(2x) + 0 + 3(1)y

dim star
dim star
snow idol
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yeah but since i already gave the answer for that one I asked for the y partial

dim star
snow idol
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yeah

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?

dim star
snow idol
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k

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why r u provocating?

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I did something wrong? xd

spare gyroBOT
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@dim star

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dim star