#Perimeter and area

38 messages · Page 1 of 1 (latest)

raw birch
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a table cover 5m × 3m, is spread on a meeting table. if 25cm of the table cover is hanging all around the table, find the area of the table top.

raw zephyrBOT
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raw zephyrBOT
cosmic heron
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Make a diagram

meager storm
cosmic heron
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Hope I helped

balmy bronze
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@raw birch draw a diagram of it, then find the length and width of the table top

raw birch
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Guyz what do you mean by draw a diagram

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I mean that's the main thing

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Ahh I'm not not getting the how to draw the diagram otherwise solving this question is not that too tough

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Didn't it?

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@balmy bronze

dapper socket
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@raw birch draw the table with dimension x × y, and then the table top of dimension 5×3 as if it laid flat over it

dapper socket
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@fringe ember you're not supposed to answer in their place

fringe ember
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You could draw two rectangles on representing the table cover and one representing the table top

dapper socket
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they can indeed solve it from the drawing, which is a good method

fringe ember
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Compare and contrast the difference in dimension

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And think about it

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What does it mean if 25cm is hanging from each side in terms of the dimension

raw birch
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I didn't got the answer yet

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I have exams day after Tommorow pls help me

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Can't you just clarify what does the question saying or give me hint to solve this @dapper socket

urban urchin
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Can't we normally say that if 25cm is hanging from all over then length of table is 5-0.5 and breadth is 3-0.5? @raw birch

fringe ember
urban urchin
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ES_whatda oh mb i didn't read that he just asked for a hint

raw birch
thin heron
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Take a look at mine too

thin heron
raw zephyrBOT
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@raw birch

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raw birch
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Now i don't need the answer my exams got over

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Sadly this question came in exam and I didn't wrote anything just left it blank

fallow copper
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you should uh, not ask the here to cheat (unless I'm getting smth wrong)

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but anyway, just imagine 4 squares in the corners or our rectangle with length 25cm, and then 4 rectangles which sides are, for each two:
(500(cm) - 25*2) * 25, since we take the length of one of those squares and the length of the edge minus the square space (trust me this makes sense)

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bla bla bla funny calculations and youuu reach this

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the first one is rectangle A, which is found twice on the 5m side, then rectangle B x2 on 3m side

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then the sum of 4 squares is .25m anddd you get the idea