#I need help

26 messages · Page 1 of 1 (latest)

rigid saddle
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my teacher, chat gpt and photomath gave me different yet similar answers. i can’t figure it out on my own, can someone help me out?

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tawny sageBOT
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tawny sageBOT
lucid junco
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What do you have to do?

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Are you supposed to rationalize the denominator?

fleet prawn
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Use (a-b)(a+b)=a²-b² a first time to get rid of a square root, and a second time to get rid of the other.

rigid saddle
rigid saddle
fleet prawn
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Depending on which you choose you may use it only once, the computations might become easier.

outer sparrow
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try pairing the 3 numbers like (root3) + (root2 +1) then take root 3 as 'a' and root2 +1 as 'b' . then multiply both numerator and denominator with (root3) - (root 2 +1) . then apply what the mimshell person said .

hearty sinew
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idk

outer sparrow
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wrong dude

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the ans is (2 + root2 - root6 )/(4)

celest breach
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also how can 1 divided by something bigger than 1 be equal to 14😭

keen trout
lucid junco
fleet prawn
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Interesting, I did not think of pairing $\sqrt2$ and $\sqrt3$. Actually isolating $\sqrt3$ in this particular case makes the computations easier as $(1+\sqrt2)^2-(\sqrt3)^2=1-2\sqrt2+2-3=2\sqrt2$.

mossy coyoteBOT
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mimshell

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tawny sageBOT
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@rigid saddle

:HelpIcon:| Help Reminder

Hello with8, this is a friendly reminder that your help request has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command. This thread will be automatically closed in 3 days if it remains inactive.

hearty sinew
lucid junco
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Sqroot 3 is not equal to 3 squared

hearty sinew
junior shadow
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the answer is the reciprocal of 3^(1/2)*2^(1/2)+1, if you can simplify it, take the sqrt values of the simplified fraction, you can solve this and find the reciprocal (i hope this isnt like "giving away the answer")

zealous schooner