limit

[twilit vigil]

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[cerulean sparrow]

say that it is less that the module of x/x+1

and for x that goes to inifnty

that limit equals 1

[formal gust]

yes you can use squeeze theorem here

divide the numerator and the denom by x

[cerulean sparrow]

perfect

[formal gust]

you get 1/[1+(sinx/x)]

[cerulean sparrow]

ohhh

[formal gust]

yeah

[cerulean sparrow]

wait i might have messed up hahaha

[formal gust]

lol

[cerulean sparrow]

wait can i sayt that x/x+1 minor to x/x+senx ?

or the opposite

ya i htink like thjis

[formal gust]

yeah

for x>0 at least

and here it is >0

[cerulean sparrow]

ah perfect then i can just apply squeeze theorem like this

[cerulean sparrow]

yea yea

[formal gust]

so works

[cerulean sparrow]

ye just messed up the inequality sign lol

[formal gust]

a better way might be to realize sinx/x would go to 0 as x approaches inf because sinx ranges from [-1, 1] and we are increasing x indefinitely in the denominator

[cerulean sparrow]

mhm idk it requires more brain power i think lol

[formal gust]

not really lol but okay

[cerulean sparrow]

well thanks anyways

bye

;close

[formal gust]

np bye

[cerulean sparrow]

how do i close

lol

,close

nvm

[twilit vigil]

@cerulean sparrow

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