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hardy bough
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Can we start by squarring both sides?

scarlet walrusBOT
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scarlet walrusBOT
hardy bough
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SO CAN we square both sides in this situation as a first stp

fast sandal
hardy bough
# fast sandal

Aryan bhai ye to thik hai but first step pe sq. Both sides krskte h?

zealous gate
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$$\left\lvert \frac{1+\cos x}{1-\cos x} \right\rvert = \left(\frac{1}{\sin x}+\cot x\right)^2$$

dusk anvilBOT
zealous gate
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you can square

hardy bough
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Okk

fast sandal
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You can, but in basic and most elegant method is that we need to prove that statement so we need to show that LHS statement equals RHS statement. Squaring both sides will meant like we have assumed that equality to be true.

zealous gate
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yes, the question is can you show an equivalent equality which is "clearly" true

hardy bough
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Alr thank you @zealous gate @fast sandal

zealous gate
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after squaring you can simplify the rhs

hardy bough
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Yes after squarring its easy

zealous gate
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$$\frac{1}{\sin x} + \frac{\cos x}{\sin x} = \frac{1+\cos x}{\sin x}$$

dusk anvilBOT
zealous gate
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and all of that squared

hardy bough
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Yep

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Thanks

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+close

scarlet walrusBOT
# hardy bough +close
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scarlet walrusBOT
# scarlet walrus

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scarlet walrusBOT
# scarlet walrus

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