#Confused About Average Rate
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By definition, the average rate of change of c is Δc/Δt. Since c(0) = 0 and we start at t = 0, that's equal to c/t.
No.
Here the starting time is t = 0, and the starting rate is also c = 0. So, Δc = c - c0 = c and Δt = t - t0 = t.
Delta, not triangle.
Delta is usually used to show the change of something. So, Δx = x(final) - x(initial).