#Please help me check if this is correct
74 messages · Page 1 of 1 (latest)
(upside down bucket)
so yk how to find the equation of quadratics with 3 points
so we know where they cross the x-axis( the solutions to the quadratic)
which is
(-48,0) and (32,0)
so x = -48 and x = 32
when we have a quadratic in the form ax^2 + bx + c
we can factorise it
into
$\alpha(x + \beta)(x + \gamma)$
curry supplier
ok so from this
the solutions to $\alpha(x + \beta)(x + \gamma) = 0$ are $x = -\beta$, $x = -\gamma$
curry supplier
and we know whta the solutions to 7c is
x = -48 and x = 32
so we know that
$-\beta = -48$, $-\gamma = 32$
curry supplier
btw im just using beta and gamma for variables you could use anything but im using this for clarity
and we want to know what $\beta$ is and what $\gamma$ is so that we can add them in our equation
curry supplier
so by multiplying both sides by -1
we get
$\beta = 48$, $\gamma = -32$
curry supplier
curry supplier
but we dont know what $\alpha$ is right?
curry supplier
heres where the third coordinate helps us
because we know that it lies on the graph we can subsititute in the x coordinates and solve for alpha
btw the whole equation is $y = \alpha(x + 48)(x - 32)$ ill expand it out later im lazy
curry supplier
so the third coordinate is (-8,-16)
from this we get y = -16, x = -8
we sub in x = -8 and y = -16to this equaeion
we get
wait
bruh im stupid i didnt need to do allat (-8,-16) is the vertex
BRUH
so we can js write this into vertex form
(vertex form is y = a(x+b)^2 + c)
vertex is (-b, c)
so we know -b = -8 and -16 = c
so the vertex form is y = a(x+8)^2 - 16
get another point so lets use (32,0)
0 = a(32+8)^2 - 16
so that means that
a(1600) - 16 = 0
a(1600) = 16
a = 0.01
i think u misread the coords of the turning point
intstead of (-8,-16) you mustve read (-8,16)
so ye now the equation is y = 0.01(x+8)^2 - 16
expand that out iyw i cba but thats the answer
@thorn hedge my answer is correct it’s just rather than 0.16x, it was 1.6x but Idk how
@unreal summit
it was not, as in 7c the coefficient of x^2 is positive, whereas yours is negative
@still merlin
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