Help me please

[noble gorge]

👋 Welcome to your Help Thread!

Hey @uneven cosmos, Thanks for sharing your math problem with us. While you wait for a Helper to help you, we want to share some vital information with you.

​

● Please take a moment to read the helpee guidelines. This will make sure that your post follows the helpee rules of our community.

​

● Please don't ping <@&775784618955505685>, <@&1283689826742440016>, <@&819616364188139550>, or <@&624327278137966593> for help because their job is to take care of the server's administrative tasks, not to answer queries directly. However, if you have a problem with how a Helper is acting, you can ping a Helper Moderator.

​

● It's always very useful if you can show us the work you've done so far. This makes it easier for our Helpers to find mistakes and help you get to the right answer.

Once you've got your answer and you're all set, you can close this thread by typing +close, and then you can click the Thank buttons to show your Helper some appreciation.

[solid scarab]

you can work in mod3

[uneven cosmos]

What is it

[solid scarab]

2 ≡ -1mod(3)

or have you not learnt it

[uneven cosmos]

Yeah

[solid scarab]

do you know the rule to prove a number is divisible by 3 in base 10?

[uneven cosmos]

Yeah

I learn it in grade 2

[solid scarab]

and do you know how that's derived?

[uneven cosmos]

My English bad sry

[solid scarab]

a number in base 10 would be something like $M = a(10)^0 + b(10)^1 + c(10)^2...$

[limpid mesa]

1significantfiguresSIGMASIGMABOY

[solid scarab]

if you divide 1, 10, 100 by 3

you get 1 as the remainder

so if a(1) + b(1) + c(1) is a multiple of 3

then it'll be divisible by 3

[uneven cosmos]

Could you explain it to me

I’m learning online

[solid scarab]

Wdym

explain which part

[uneven cosmos]

so if a(1) + b(1) + c(1) is a multiple of 3

This part

[solid scarab]

Yes so a(1) + b(1) + c(1) is the total remainder if you divide M by 3

and if the remainder is divisible by 3

[uneven cosmos]

OK thanks

[solid scarab]

then the whole thing is divisible by 3

Np

that's why the rule works

you just add the digits

[uneven cosmos]

Why my teacher said im wrong 😭😭

[solid scarab]

Wdym

[uneven cosmos]

I’m learning online

She said

M =(2^1+2^2)+(2^3+2^4)+…+(2^99999+2^100000)

M=2(1+2)+2^3(1+2)+…+2^99999(1+2)

[solid scarab]

Oh

that works aswell

[uneven cosmos]

2.3+2^3.3+…+2^99999.3

Because 3 divisable by 3

[solid scarab]

yeah

[uneven cosmos]

M will divisable by 3

And I’m Asian

The math is so hard

[solid scarab]

I mean, it's just factorising each pair.

[uneven cosmos]

My teacher said it’s grade 3 knowledge

But anyway

Thanks for helping me

[solid scarab]

Np

[noble gorge]

@uneven cosmos

:HelpIcon:| Help Reminder

Hello duyskibidi0237_85670, this is a friendly reminder that your help request has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command. This thread will be automatically closed in 3 days if it remains inactive.