#Partial fractions

21 messages · Page 1 of 1 (latest)

worn finch
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How would I get the term for A?
I thought you could only get 2 terms in fractions as there are only 2 for below the fraction

hasty heathBOT
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hasty heathBOT
mint glacier
worn finch
mint glacier
worn finch
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Ohhhh I see

mint glacier
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Basically, when integrating rational functions, you need to make sure your function is a proper fraction. If not, then divide first.

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The remainder will always be a proper fraction, and you can use partial fractions on it.

worn finch
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Like this?

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@mint glacier

mint glacier
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Uh, no. I'm not even sure what you did.

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You need to divide 2x^2 - 2x - 9 by x^2 + x - 2.

worn finch
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Oh

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I just divided it by (1-x) and (2+x) then added them together

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Wouldn't that just be the same output?

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@mint glacier

mint glacier
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No.

worn finch
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Oh.

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Alr then

hasty heathBOT
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@worn finch

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