Interesting question | Mathematics | Page 1

fast flumeBOT Oct 4, 2025, 2:55 PM

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covert mist Oct 4, 2025, 4:15 PM

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is it 2n! or (2n)! ?

near flax Oct 4, 2025, 4:15 PM

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covert mist is it 2n! or (2n)! ?

The first one

covert mist Oct 4, 2025, 4:17 PM

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Ok, post your attempt

near flax Oct 4, 2025, 4:19 PM

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n=p-1 it is an condition that isnt require this equation

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My english isnt so good if you cant understand say me

covert mist Oct 4, 2025, 4:20 PM

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I don't fully get what you mean

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I assume p is a prime?

near flax Oct 4, 2025, 4:20 PM

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covert mist I assume p is a prime?

Yes

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If p prime n=p-1 isnt an integrr

covert mist Oct 4, 2025, 4:21 PM

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you mean the expression with that n value?

near flax Oct 4, 2025, 4:21 PM

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covert mist you mean the expression with that n value?

Yes

covert mist Oct 4, 2025, 4:21 PM

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cause if p is prime, certainly p-1 is an integer

near flax Oct 4, 2025, 4:22 PM

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I solve only this case

covert mist Oct 4, 2025, 4:22 PM

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I mean, 24 is a relatively small number in the grand scheme of things

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and you've just removed a good chunk of the possible n values

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worst comes to worst you can just run the list

near flax Oct 4, 2025, 4:23 PM

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I want to know wihout putting numbers

covert mist Oct 4, 2025, 4:23 PM

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But yes, $n=p-1$ doesn't work for odd primes since it'd require $p$ to be a factor of $2(p-2)!$

worthy grottoBOT Oct 4, 2025, 4:24 PM

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Omega

covert mist Oct 4, 2025, 4:29 PM

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near flax I want to know wihout putting numbers

Im pretty sure all odd numbers necessarily will work, as for evens you have to argue about the number of factors of 2 in each 2(n-1)! and n+1 I think?

quartz vineBOT Oct 5, 2025, 5:00 PM

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@near flax

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#Interesting question