#Physics help perchance? 😭

26 messages · Page 1 of 1 (latest)

tall nebula
#

Im not too sure if my solution is right, but either way any help is appreciated!

trail lichenBOT
#
  1. Do not ping the Moderators, unless someone is breaking the rules.
  2. Do not ping the Helper Moderators, unless there is a conflict between helpers.
  3. Do not ping other members randomly for help.
  4. Ask your question and show the work you've done so far. If you've posted a screenshot of a question, specify which part you need help with.
  5. Wait patiently for a helper to come along.
  6. If the Helper has answered your question, remember to thank them with the Mathematics Ranks bot and close the thread with:

+close
Feel free to nominate the person for helper of the week in #helper-nominations
If you're happy with the help you got here, and the server overall, you can contribute financially as well:

eager phoenix
tall nebula
#

I made it Δm=PVM/R(1/T2-1/T1)

eager phoenix
#

it is correct right?

#

do u wanna know how to get the answer or u figured?

tall nebula
#

I think so 😭

eager phoenix
#

so u know the volume and molar mass dont change

#

and also the pressure

#

so u take PV=nRT

#

and n = mass/Molar mass

#

so PVM = mRT

#

PVM/R = Tm

#

so now on the right everyhting is constant

#

so for ever T,m their product will be same i.e.

#

m1 T1= m2T2

#

so m2= m1*T1/T2

distant vale
eager phoenix
#

then u write m1 - m2 = m1 (1- t1/t2)

distant vale
#

Though, you can do it more simply. We have:
m = pVM/RT = (pVM/R)(1/T)
Notice that I isolated everything that is constant. So:
Δm = (pVM/R)Δ(1/T) = (pVM/R)(1/T2 - 1/T1)
Which is the same as what you have.

eager phoenix
#

m1 = PVM/RT1

#

yeah same

deft plankBOT
#

@tall nebula

:HelpIcon:| Help Reminder

Hello ohkonijn, this is a friendly reminder that your help request has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command. This thread will be automatically closed in 3 days if it remains inactive.