#Algebra
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Which part?
Do you want me to demonstrate just one?
And you can do the rest?
ok, I will demonstrate Q2 since Q1 is too easy and won't give a proper idea of how to do the rest
Okay
So, we have $5x+y=23$ AND $2x+y=11$ and we are supposed to find $x,y$ that satisfy these equations
wolfqz
Do you understand what the term "coefficient" means?
Yes
alright
in the equation 5x+y=23
there are x,y variables
the "coefficient" of x is 5
Ohh okay
as you can see, it is just the constant term multiplied with x
Yes
okay, can you tell me coeff of x in 2x+y=11?
and what about the coeff of y?
yaahh u said neither so it's generally assumed u meant values
but it's okay
u said the correct coefficients
anyways, you realize that if we multiply both sides of an equation by the same number, then the equation is equivalent to the original
uhh....
yea
yea that's what i was saying
oh okay
what happens if u multiply both sides of 2x+y=11 by 5?
10x and 5y?
10x+5y=(what?)
55???
Oh word
what if we now multiply both sides of 5x+y=23 by 2?
10x + 2y = 46
Okay that makes me feel way better
We have this two equation
What if we just subtract this two equations?
55 - 46?
And the left hand side?
don't the 10x cancel each other out
and 5y - 2y = 3y
so 3y = 9?
i might be a lost cause
No?
2x + 3 = 11
So we found x as well.
2x=8 yes then x=4
x = 4?
yess
Okay
$5x+y=23$ AND $2x+y=11$
wolfqz
we multiplied both these equations with some constant
But the constants were very special
They made the coefficient of x the same
And when the coefficients were the same, we just subtracted the equations
5x - 2x?
BECAUSE when the coefficients were the same, we knew subtracting the equations would lead to one of the variables being eliminated
Yes, u can also do that
yes
I was getting to that
o
That rn what we did was ELIMINATE x
sorry
We can also ELIMINATE y
noworries, it was pretty smart of u to notice that actually
Yes
In this case, we can also subtract these equations directly thus eliminating y
Can you try Q3 now, just tell me what answers u get after solving them and i'll confirm if u did it correctly or not
okay do you want me to type the working out here
so you can see where i go wrong
if i do*
first, just type the answer
okay
if it's right then i don't require a working out
ofcourse just write it in ur exam ๐ฅ
2x + 3y = 3
5x + 3y = 12
(so I dont have to go back to the top)
im lost sorry ๐
i tried 5x - 2x
Then?
no idea man
wait, i am so sorry I gotta go eat my food ๐
no worries
i will be back in no more than 30 mins
ping me when ur back
I'm back @honest lark
again, sorry for having to go.
I only got like an hour until I have to go
ok no worries @stark apex
read this
ts subtracting the equations
the - sign distributes
5x+3y-2x-3y=9
why do you minus the 3y by 3y
.
So that we can get rid of y
ah ok
Since we already know how to solve an equation in one variable
So we will convert a problem with two variables and two equations into a one variable
so 5x - 2x basically?
3x = 9?
yesshh
y=-1 you mean
oh ye whoops
yeah
to eliminate m you will have to multiply the first eqn wtih 5 and second with 3
to eliminate n u just have to subtract
Nice
What's the other side
2m
o
I did what you did before.
i mean it's the correct expression but the ordering is a bit off so im scared u didnt subtract properly
5m-4n-(3m-4n)=-22-(-18)
Ok
can you give me a tip on what to do next
wait
2m=-4
oh your back
I have to go in like 10 minutes
I will be back tmrw but like, you don't have to help if you don't want to.
Like alg
i was taking a shower bruh
๐ฅ
@stark apex
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