#Complex Numbers
36 messages · Page 1 of 1 (latest)
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rq i know how to solve this normally
but i dont understand
this method
like i know how to get to the simultaneous equation
but not what you do after
you have a system of equations to solve for a and b, so the usual processes for that
oh do i solvve
the simultaneous equations
?
and expand the bracket
finding a and b
well.. substitution or elimination again like usual
?
you have the system 2a+3b=p and 3a-2b=4
clearly those equations are equivalent to 6a+9b=3p and 6a-4b=8, subtracting the 1st from the 2nd gives 13b=3p-8
hence you have b = (3p-8)/13
hence you can get a
alternatively, you just multiply the initial numerator and denominator by the denominator's conjugate, just like you've likely done with radicals (sqrt(a)-sqrt(b) type denominators)
@surreal oasis
alr
but yeah.. it's just knowledge you should already have in either case
the prior especially, the latter the same general idea
well im doing stuff a year ahead
thats why
but i understand that
+close
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