Definite Integration | Mathematics | Page 1

prisma badger Jun 17, 2025, 3:10 PM

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how to evaluate this 9th question

vale craneBOT Jun 17, 2025, 3:10 PM

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prisma badger how to evaluate this 9th question

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royal lodge Jun 17, 2025, 3:14 PM

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prisma badger how to evaluate this 9th question

im not sure if its the fastest method or not

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but did you calculate the differentiation part??

prisma badger Jun 17, 2025, 3:20 PM

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no

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bhai allen ka module hai

royal lodge Jun 17, 2025, 3:27 PM

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prisma badger bhai allen ka module hai

toh kya hua 💀

royal lodge Jun 17, 2025, 3:27 PM

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prisma badger no

kar fir

weak fractal Jun 17, 2025, 4:12 PM

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prisma badger how to evaluate this 9th question

Remember the fundamental theorem of calculus.

prisma badger Jun 17, 2025, 5:13 PM

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bata raha hu

prisma badger Jun 17, 2025, 5:13 PM

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weak fractal Remember the fundamental theorem of calculus.

i did it but the book says the answer is wrong

weak fractal Jun 17, 2025, 5:14 PM

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prisma badger i did it but the book says the answer is wrong

What answer?

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There's two things that could be happening here that I can see. One is that you applied the FTC incorrectly. The other is that your answer and the book answer are actually just different expressions of the same number.

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Oh, also this function is discontinuous at x = 0, so you might want to split the integral and take the components improperly.

prisma badger Jun 17, 2025, 5:21 PM

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yes thats what i did

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i splitted it

weak fractal Jun 17, 2025, 5:22 PM

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Show your work.

prisma badger Jun 17, 2025, 5:24 PM

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see

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i cutted it but just ignore that

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book says that it is 2/(1+e)

weak fractal Jun 17, 2025, 5:31 PM

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prisma badger see

What is "(-> 0)"?

prisma badger Jun 17, 2025, 5:32 PM

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tending to zero

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so that it can be neglected

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actually i am going to sleep now

weak fractal Jun 17, 2025, 5:47 PM

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prisma badger tending to zero

...does it though?

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We're talking about $\lim_{x \to 0^-} \frac{1}{1 + e^{\frac{1}{x}}}$, right?

summer lintelBOT Jun 17, 2025, 5:47 PM

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Techie Literate

weak fractal Jun 17, 2025, 5:48 PM

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On the right.

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And on the left it's $\lim_{x \to 0^+}\frac{1}{1 + e^{\frac{1}{x}}}$.

summer lintelBOT Jun 17, 2025, 5:48 PM

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Techie Literate

prisma badger Jun 18, 2025, 1:48 AM

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yes

prisma badger Jun 18, 2025, 11:21 AM

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oh i get it

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$\lim_{x \to 0^-}\frac{1}{1+e^{\frac{1}{x}}} = 1$

summer lintelBOT Jun 18, 2025, 11:23 AM

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Robo_17

prisma badger Jun 18, 2025, 11:23 AM

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and

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$\lim_{x \to 0^+}\frac{1}{1+e^{\frac{1}{x}}} = 0$

summer lintelBOT Jun 18, 2025, 11:24 AM

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Robo_17

prisma badger Jun 19, 2025, 12:10 AM

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+close

obtuse edgeBOT Jun 19, 2025, 12:10 AM

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prisma badger +close

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#Definite Integration