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[whole jacinth]

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[cerulean lantern]

Question 55

Can write |[x]| = 1

Then what do i do

[zinc olive]

,rccw

[zinc olive]

Is [x] the floor function?

Nevermind its right there

[zinc olive]

🤨

[x] is the floor function, so it shouldn't be 1

[cerulean lantern]

there is a mod outside it

[0^-] = -1

[zinc olive]

Ah, ok

[cerulean lantern]

now, what do i do next 😭

[zinc olive]

Invoke the definition of {x}

Then it should reduce to a simple(r) limit

[cerulean lantern]

x - [x] ??

[zinc olive]

Yes

[cerulean lantern]

so like

it becomes

{x} = x+1

i cant find it usefull

[zinc olive]

It simplifies the limit on the inside

And in the exponent

[cerulean lantern]

(ln(x+2))^(x+1) ??

[zinc olive]

Yes

[cerulean lantern]

bro fuck i can just put x = 0 inside it 💀

BROOOOO\

HOYI 😭

[cerulean lantern]

I WAS PUTTING {x}= 0

NOO WAYY

{0^-} = 1^- NOT 0 😭

[cerulean lantern]

+close

[azure flame]

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