#Combinatorial game theory

28 messages · Page 1 of 1 (latest)

sharp dome
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Alice and Bob have been given a composite number N. In each move, a player writes down a composite divisor of N on the board such that there are no two numbers on the board that divde each other or no two numbers that are co prime. Alice plays first. The player who cannot make a move looses Who has the winning strategy? (The book i am solving has a hint that Alice has the winning strategy but that makes no sense to me. Shouldn't it depend on what is N. A counterexample is N= p^2. N is composite and alice cannot make a move since N has no composite divisors. Similarily you can prove that in p1p2 Bob has a winning strategy. Am i misunderstanding the question?)

serene schoonerBOT
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rugged patrol
sharp dome
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okay

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The number N is the product of k diferent primes (k ≥ 3). Two
players play the following game. In turn, they write composite divisors of N on a blackboard. One may not write N. Also, there may
never appear two coprime numbers or two numbers, one of which
divides the other. The first player unable to move loses. Does the
first player or the second player have a winning strategy?

sharp dome
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and there was a gross printing mistake in the description of the same problem in the book i was using

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fuck

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they didn't inlcude the fact that N is product of k different primes

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The book i am using is quite new. It was published in 2025

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or maybbe 2024

grave lark
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@sharp dome take a picture of the problem

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and send it

rugged patrol
sharp dome
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Its alright

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theres no point in sending the screenshot when I know that problem statement is incomplete

sharp dome
tame stag
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Also are you doing this recreationally or for school?

Also also, how good are you at this. Im not exactly the sharpest tool in the shed and I dont wanna waste your time if a. This is for school or b. You are already way more well versed than me

sharp dome
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I am studying for context math

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*contest

alpine rampart
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for example N = pqr

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the divisors are pq, qr, pr

cold topazBOT
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@sharp dome

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