#q33 dynamics
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definite integration ?
but will I be able to use definite integration for example from 2 to 5
as he didn't put less than or egual ?
The first piece includes s = 2.
Other than that, yeah, just integrate. After all, the change in kinetic energy is just work done by the force.
so change in kinetic energy equals work done
Yes.
so therfore
change in potential energy = - work done?
right?
he didn't ask about it in that question
but for future questions it might help
Why minus?
Other than that, yes.
By definition, dW = F·dl.
isn't W=change in kinetic ?
and change in potential = -change in kinetic
W is for work
Oh, sorry, didn't notice the potential energy.
Yeah, if we're talking about the potential energy, there will be a minus.
noted
After all, since U + T = E = const, that means dU = -dT. Thus, dW = dT = -dU.
(assuming no dissipation of energy, of course)
a way of showing respect
in my culture
Regardless of age just for showing respect
Oh. Hm, ok.
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