#Grade 10 CBSE problem
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What have you tried?
so since it has infinite solutions
i did a1/a2 = b1/b2 = c1/c2
i solved the first two fractions
and got a = 5b
What?
do you know the curiculum?
...no, obviously not, because I'm not your classmate.
ok then u wouldn't know
Just because I don't know "the curriculum", i.e. what you specifically, personally have been taught, doesn't mean I don't know how to solve the problem.
oh ok
What I don't understand is what you have done and why.
ill try to explain what those values in the fraction are
and then u can solve it
so lets take 2x + 3y = 7 and 6x + 9y = 21
6x + 9y = 21?
Why don't we use the example we have?
ok fine'
2x + 3y = 7
(a-b)x + (a+b)y = 3a + b - 2
in an equation with two variables
it is ax + by = c
since there is 2 equation
Wait, hold on.
Okay.
I think using a, b, and c in this way is going to be unnecessarily confusing.
but like it is the general form of a linear equation
No it very much is not.
linear equation not quadratic
my bad
anyway
so if its a pair
the equations will be represented like this
Okay...
now you compare a1 and a2
so a1/a2
do the same for other values
so in the question i gave
a1 is 2 and b1 is (a-b)
so it will be 2/(a-b)
...I don't think so.
Okay, I wonder at this stage if you understand conceptually what's happening here.
i do
because this is what is there in grade 10
can i give u a picture to explain this concept
Do you understand what "coincident lines" means?
Which actually means the two equations are describing the same line.
Find values of a and b if the equations have infinite solutions.
2x + 3y = 7
(a-b)x + (a+b)y = 3a + b - 2
here u go
...yes, that's the problem.
now solve a1/a2 = b1/b2
...we're not here to do your homework for you.
We're here to help you do your homework.
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