#How would I love this problem?

75 messages · Page 1 of 1 (latest)

gray aurora
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This a part of my study guide for my final exam tomorrow. I tried to ask my teacher how to solve it and she just gave me the answer and didn't explain it. Could someone help?

magic ravenBOT
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gray aurora
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"Line segment EF has a distance of 10 units, and the cordnits of E are (14,-6) wich cordnits COULD represent the mid point of EF?

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(-10,-9)

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(-14,11)

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(11,-2)

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(11,10)

west steeple
west steeple
# gray aurora 1,5, and 10 right?

Please be more concise with what you mean by 1,5 and 10.

A midpoint bisects a line segment, meaning that the distance from a midpoint M to either endpoint E or F should be equal to one another. Understanding this notion, what should the length of EM (or FM) be?

tiny lily
golden nexus
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Therefore

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Ur midpoint is at (19,-6)

gray aurora
golden nexus
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?

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Oh

gray aurora
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I listed the choices lol

golden nexus
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Could the line just be a line along the y axis?

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Therefore add 5 to the y?

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Your answer should be (14,1)

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If that's true

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Tahts not their either

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Argh

gray aurora
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From what I rember my teacher said something among the lines that we know the line is 10 units. So the mid point would have to be 5 units away from E. Then you check and see wich one could be it?

golden nexus
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I just said tha

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We add 5 to 14 you get 19 which is not there, add 5 to -6 which is also not there

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Why tf is there -14

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Gimme a sec I'm drawing a diagram

gray aurora
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K

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I think the answer was A now that I'm looking at what I circled

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Though I have no clue how that's the answr

west steeple
west steeple
golden nexus
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Hm

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Let's eliminate answers

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I'm gonna crash out

gray aurora
golden nexus
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The answers don't match upp

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Unless we're taking units literally

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I'm trying my best 😔

west steeple
golden nexus
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Alr

gray aurora
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Since the y coordinate is 5 units away from E's Y coordinate

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?

west steeple
gray aurora
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5 on the y and 28 on the X?

golden nexus
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No

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Uhh

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28 units

gray aurora
west steeple
# gray aurora 5 on the y and 28 on the X?

No. The distance between two points is given by the formula d = sqrt[(x2-x1)^2 + (y2-y1)^2]. I'm assuming that you added the x and y-coordinates together to arrive at those answers (although you should only have one numerical value to represent the length).

I'll set up the question for you to solve for answer choice a. Find the distance between the two points (-14, 11) and (14, -6) when:
x1 = -14
x2 = 14
y1 = 11
y2 = -6
Use the formula above.

golden nexus
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...

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√(14-(-14))²+((-6)+11)²
For the first bracket,
14²-2(14)(-14)+(-14)²
196-392+196
(-196)+196
=0

Second bracket
(-6)²-2(-6)(11)+11²
36-132+121
(-96)+121
25.
Your root now is
√0+25
√25
=5

west steeple
slender rampart
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It’s just any point at a distance of 5 units from E

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@gray aurora

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Naturally, they would’ve given only one such point as an option

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So just check each option

slender rampart
umbral flax
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Wtf just write the equation of circle of radius 5 and centre at E check which points satisfy

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(x-14)² + (y+6)² = 25

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C satisfies

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@gray aurora

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If you dont know equation of circle you can get the same result by using dist formula

From E to (x , y) should be 5units

Sqrt((x-14)² + (y+6)²) = 5

slender rampart
slender rampart
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But, otherwise, yeah

umbral flax
lime sentinelBOT
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@gray aurora

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