#How would I love this problem?
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"Line segment EF has a distance of 10 units, and the cordnits of E are (14,-6) wich cordnits COULD represent the mid point of EF?
(-10,-9)
(-14,11)
(11,-2)
(11,10)
Use your knowledge of the characteristics of a midpoint and the distance formula to help you solve this problem.
We're given the fact that the segment EF has a length of 10 units. What should the length from the midpoint to the endpoint be, on either side of the segment?
1,5, and 10 right?
Please be more concise with what you mean by 1,5 and 10.
A midpoint bisects a line segment, meaning that the distance from a midpoint M to either endpoint E or F should be equal to one another. Understanding this notion, what should the length of EM (or FM) be?
line segment EF presumably has a LENGTH of 10, so the point F would be 10 units away from the point E
the midpoint would be how many units away from E?
then just plug the answer choices in the distance formula
Ok so we know that e is at (14,-6) in the bottom right quadrant. 14x and -6y. We also know that EF is 10 units long therefore F must be at 14+10=24x. To find the midpoint of the line segment, use half the length of EF and add to E.
14+(10/2)=14+5=19
Therefore
Ur midpoint is at (19,-6)
But that's not an option
I listed the choices lol
Could the line just be a line along the y axis?
Therefore add 5 to the y?
Your answer should be (14,1)
If that's true
Tahts not their either
Argh
From what I rember my teacher said something among the lines that we know the line is 10 units. So the mid point would have to be 5 units away from E. Then you check and see wich one could be it?
I just said tha
We add 5 to 14 you get 19 which is not there, add 5 to -6 which is also not there
Why tf is there -14
Gimme a sec I'm drawing a diagram
K
I think the answer was A now that I'm looking at what I circled
Though I have no clue how that's the answr
Yes. Find the distance between the point E and the four options given, and see which answer yields 5 units.
It's not.
Ok
?
The answers don't match upp
Unless we're taking units literally
I'm trying my best 😔
If this question is troubling you, please refer to the advice given beforehand. Else, you are confusing the OP.
Alr
So wait. The mid point is 5 away from the point and we are looking for points that Could be the mid point wouldt that make the answer B?
Since the y coordinate is 5 units away from E's Y coordinate
?
What is the distance between the points (-14,11) and (14,-6)?
5 on the y and 28 on the X?
14 units
No
Uhh
28 units
Or could it be C? Since the distances on both the X and Y are less than 5? I'm honestly quite confused
No. The distance between two points is given by the formula d = sqrt[(x2-x1)^2 + (y2-y1)^2]. I'm assuming that you added the x and y-coordinates together to arrive at those answers (although you should only have one numerical value to represent the length).
I'll set up the question for you to solve for answer choice a. Find the distance between the two points (-14, 11) and (14, -6) when:
x1 = -14
x2 = 14
y1 = 11
y2 = -6
Use the formula above.
It's 5 units
...
√(14-(-14))²+((-6)+11)²
For the first bracket,
14²-2(14)(-14)+(-14)²
196-392+196
(-196)+196
=0
Second bracket
(-6)²-2(-6)(11)+11²
36-132+121
(-96)+121
25.
Your root now is
√0+25
√25
=5
Recheck you arithmetic on -2(14)(-14), as well as -2(-6)(11). You also unnecessarily performed binomial expansion when you could've just added both integers before squaring the sums.
I do not want to go as far as to say that these errors were deliberate, but your continuously questionable inputs make me think otherwise.
It’s just any point at a distance of 5 units from E
@gray aurora
Naturally, they would’ve given only one such point as an option
So just check each option
- You do NOT need to use the binomial expansion
- Two negatives when multiplied, give a positive as the answer. (You forgot this twice)
- It’s -6-11 not -6+11
- You also wrote 6 as -6 but then incorrectly multiplied it as if it didn’t have a negative sign anyway, so at least that didn’t cause any trouble. (Still very wrong)
Wtf just write the equation of circle of radius 5 and centre at E check which points satisfy
(x-14)² + (y+6)² = 25
C satisfies
@gray aurora
If you dont know equation of circle you can get the same result by using dist formula
From E to (x , y) should be 5units
Sqrt((x-14)² + (y+6)²) = 5
You wrote x twice
Both times
But, otherwise, yeah
Yeah mb
@gray aurora
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