Phsyics Circuit Problem Part 2 | Mathematics | Page 1

carmine path May 19, 2025, 1:26 AM

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gaunt falconBOT May 19, 2025, 1:26 AM

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carmine path

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carmine path May 19, 2025, 1:27 AM

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we got solved for IT and RT but we are confused as to what to do next

copper pollen May 19, 2025, 1:28 AM

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So solve the easy ones first, V11 and V10

carmine path May 19, 2025, 1:28 AM

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ok makes sense let me do it rq

copper pollen May 19, 2025, 1:29 AM

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Then consider the parallel system of R1 and R2

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We need the total resistance of this parallel section

carmine path May 19, 2025, 1:30 AM

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so for v10 its 29.6 and for v11 its 100.64

carmine path May 19, 2025, 1:31 AM

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copper pollen We need the total resistance of this parallel section

so r3456789 we got 15.5 for it

fallow cosmos May 19, 2025, 1:31 AM

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15.6*

copper pollen May 19, 2025, 1:31 AM

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Do you guys know that we can treat the parallel system R1 and R2 as 1 resistor?

carmine path May 19, 2025, 1:32 AM

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ya

sick meteor May 19, 2025, 1:32 AM

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yes

carmine path May 19, 2025, 1:32 AM

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cus they converge at the end right

copper pollen May 19, 2025, 1:32 AM

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Yeah sort of

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So calculate the resistance of it

fallow cosmos May 19, 2025, 1:33 AM

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copper pollen Do you guys know that we can treat the parallel system R1 and R2 as 1 resistor?

So u combine them and make it a single residtor with 8 ohms?

copper pollen May 19, 2025, 1:33 AM

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Yeah exactly

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So you can find the total voltage the system uses

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Since it gets the total current

carmine path May 19, 2025, 1:34 AM

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ok so we finding v1 and v2 correct

copper pollen May 19, 2025, 1:34 AM

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Yes

fallow cosmos May 19, 2025, 1:34 AM

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Ohhh so V1+V2 will equal 23.68?

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Because 8*2.96

copper pollen May 19, 2025, 1:35 AM

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Hm,

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V1 or V2

carmine path May 19, 2025, 1:35 AM

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v12

fallow cosmos May 19, 2025, 1:35 AM

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When you combine them they become v12

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So v12 has a total voltage of 23.68

copper pollen May 19, 2025, 1:35 AM

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V1 = V2

carmine path May 19, 2025, 1:36 AM

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oh ya

fallow cosmos May 19, 2025, 1:36 AM

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So V1 = V2 = 2.96*8

copper pollen May 19, 2025, 1:37 AM

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Yeah, voltage is the same across all branches

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For parallel circuits

carmine path May 19, 2025, 1:37 AM

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ok so we do 200 - 23.68 to see how much voltage goes into the other branches

fallow cosmos May 19, 2025, 1:37 AM

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Wait not yet

copper pollen May 19, 2025, 1:37 AM

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And also minus V11 and V10

carmine path May 19, 2025, 1:38 AM

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wait so is v12 = v1 = v2?

copper pollen May 19, 2025, 1:38 AM

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Yup

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You got the voltage of the whole system

fallow cosmos May 19, 2025, 1:38 AM

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But v10 and 11 is series

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So they dont equal eachother

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Right

copper pollen May 19, 2025, 1:39 AM

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Yeah

carmine path May 19, 2025, 1:39 AM

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so we do 200 - 23.68 - 100.64 - 29.6

copper pollen May 19, 2025, 1:40 AM

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I think so

silver elk May 19, 2025, 1:40 AM

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It doesn’t seem too hard, it’s just lengthy

copper pollen May 19, 2025, 1:40 AM

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So you check that if you multiply It by the total resistance of the other parallel system

carmine path May 19, 2025, 1:41 AM

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silver elk It doesn’t seem too hard, it’s just lengthy

its hard to us😭

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ok so we got

silver elk May 19, 2025, 1:41 AM

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carmine path its hard to us😭

Where you at now?

fallow cosmos May 19, 2025, 1:41 AM

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silver elk It doesn’t seem too hard, it’s just lengthy

Our teacher is horrible

sick meteor May 19, 2025, 1:41 AM

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fallow cosmos Our teacher is horrible

_catdespair

carmine path May 19, 2025, 1:41 AM

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so we got 46.08

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for the reaminving volatge going to each branch

copper pollen May 19, 2025, 1:43 AM

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Did you get like 52.31

carmine path May 19, 2025, 1:43 AM

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we got 46.08

copper pollen May 19, 2025, 1:43 AM

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Oh wait nvm.

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Yeah I got that too

carmine path May 19, 2025, 1:44 AM

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ok nice

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so what do we do next

fallow cosmos May 19, 2025, 1:44 AM

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So V3 + V4 = Vt, And V5 + V6 + V7 = Vt, and V8 + V9 = Vt
Sorry not vt

copper pollen May 19, 2025, 1:44 AM

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Each branch has the same voltage, you can calculate current then use V = IR to get the voltage of each component

silver elk May 19, 2025, 1:44 AM

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carmine path so what do we do next

For which one?

copper pollen May 19, 2025, 1:44 AM

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Treating each path as a series circuit

carmine path May 19, 2025, 1:45 AM

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like in general after we find the remeaning volatge going to each branch which was 46.08

copper pollen May 19, 2025, 1:45 AM

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So you know how current is the same in series circuits

carmine path May 19, 2025, 1:46 AM

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ya

fallow cosmos May 19, 2025, 1:46 AM

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copper pollen Treating each path as a series circuit

So V3 V4 V5 V6 V7 V8 V9 all equal 46.08

carmine path May 19, 2025, 1:46 AM

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So V3= V4= V5= V6= V7= V8= V9 all equal 46.08

copper pollen May 19, 2025, 1:46 AM

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fallow cosmos So V3 V4 V5 V6 V7 V8 V9 all equal 46.08

The sum of voltages for Each path

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Not all paths

fallow cosmos May 19, 2025, 1:46 AM

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Ahhh alr

carmine path May 19, 2025, 1:46 AM

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ok got it

neon orbit May 19, 2025, 1:47 AM

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If you want to learn yourself, simply watch the conversation.

carmine path May 19, 2025, 1:47 AM

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?

copper pollen May 19, 2025, 1:47 AM

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So you can calculate the current, you can divide the voltage by the total resistance

carmine path May 19, 2025, 1:47 AM

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we are in the same class working on it together

copper pollen May 19, 2025, 1:47 AM

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Of each path

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I = V/R

fallow cosmos May 19, 2025, 1:48 AM

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But we dont have the velocities

sick meteor May 19, 2025, 1:48 AM

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does I34 = It?

copper pollen May 19, 2025, 1:48 AM

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Hm?

fallow cosmos May 19, 2025, 1:49 AM

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What is the next step im a lil confusd

carmine path May 19, 2025, 1:49 AM

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i am as well

copper pollen May 19, 2025, 1:49 AM

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Ok let's focus on the first branch

fallow cosmos May 19, 2025, 1:49 AM

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Okay

copper pollen May 19, 2025, 1:49 AM

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What's the total resistance of the first branch

sick meteor May 19, 2025, 1:49 AM

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30?

fallow cosmos May 19, 2025, 1:49 AM

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30

copper pollen May 19, 2025, 1:49 AM

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So what's the current in the first branch

fallow cosmos May 19, 2025, 1:50 AM

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23.68/30?

copper pollen May 19, 2025, 1:50 AM

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Huh

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Where did 23.68 come from

sick meteor May 19, 2025, 1:50 AM

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voltage??

fallow cosmos May 19, 2025, 1:50 AM

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copper pollen May 19, 2025, 1:51 AM

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carmine path we got 46.08

We got 46.08 as the voltage going into each branch right guys?

fallow cosmos May 19, 2025, 1:51 AM

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OHHHH

carmine path May 19, 2025, 1:51 AM

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yes

fallow cosmos May 19, 2025, 1:51 AM

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MY BAD

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so 46.08/30

copper pollen May 19, 2025, 1:51 AM

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Yeah

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So now can you calculate the voltage of each component?

carmine path May 19, 2025, 1:51 AM

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so we do 46.08 / 30

sick meteor May 19, 2025, 1:52 AM

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1.536

fallow cosmos May 19, 2025, 1:52 AM

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So 134=1.536

copper pollen May 19, 2025, 1:52 AM

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Yeah

carmine path May 19, 2025, 1:53 AM

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ok and then we do that for the other 2

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ok

fallow cosmos May 19, 2025, 1:53 AM

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And 1567 = 46.08 divided bu the total resistance of I567

copper pollen May 19, 2025, 1:53 AM

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Yeah

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I3 + I5 + I8 should sum to It

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Might want to check that

carmine path May 19, 2025, 1:54 AM

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i567 = 0.658

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and 89 = 0.768

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ok let me check

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i34 = 1.536

copper pollen May 19, 2025, 1:55 AM

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Yeah I think it does sum to It

carmine path May 19, 2025, 1:56 AM

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but i got 1.426 instead of i3 which is 1.536

fallow cosmos May 19, 2025, 1:56 AM

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carmine path but i got 1.426 instead of i3 which is 1.536

U wrote sum wronh

copper pollen May 19, 2025, 1:56 AM

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Wait guys

fallow cosmos May 19, 2025, 1:57 AM

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I1=I2= i presume

sick meteor May 19, 2025, 1:57 AM

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yea

fallow cosmos May 19, 2025, 1:57 AM

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Not sure ngl

sick meteor May 19, 2025, 1:57 AM

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im guessing its the same as iT?

fallow cosmos May 19, 2025, 1:57 AM

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Im pretty sure I12= I1+I2

carmine path May 19, 2025, 1:57 AM

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i1 and i2 are differennt values

carmine path May 19, 2025, 1:57 AM

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fallow cosmos Im pretty sure I12= I1+I2

ya

fallow cosmos May 19, 2025, 1:57 AM

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So we dont have to solve for I1 and I2 individually

copper pollen May 19, 2025, 1:57 AM

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Ohh

silver elk May 19, 2025, 1:57 AM

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Wait, what did you get as I for the whole circuit?

fallow cosmos May 19, 2025, 1:58 AM

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2.96

carmine path May 19, 2025, 1:58 AM

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2.96

silver elk May 19, 2025, 1:58 AM

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Same

carmine path May 19, 2025, 1:58 AM

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i see

fallow cosmos May 19, 2025, 1:59 AM

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This is what we have so far

copper pollen May 19, 2025, 1:59 AM

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I12 would just be It wouldn't it?

carmine path May 19, 2025, 1:59 AM

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correct

fallow cosmos May 19, 2025, 1:59 AM

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He js tryna trick us

carmine path May 19, 2025, 2:00 AM

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fallow cosmos He js tryna trick us

the teacher

fallow cosmos May 19, 2025, 2:00 AM

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Yes

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Mb for no clarification

carmine path May 19, 2025, 2:00 AM

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so we got the I values

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now we have to get the V values collect

copper pollen May 19, 2025, 2:00 AM

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You got the current in each branch, and the resistance of each component

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How do you get voltage

carmine path May 19, 2025, 2:01 AM

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v = IR

copper pollen May 19, 2025, 2:01 AM

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Yeah

carmine path May 19, 2025, 2:01 AM

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ohh wait i see

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WAIT I SEE

sick meteor May 19, 2025, 2:01 AM

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WE SEE I GOT IT

carmine path May 19, 2025, 2:03 AM

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ok we are gonna work on it right now

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man this takes a while

copper pollen May 19, 2025, 2:05 AM

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I think you guys already calculated the resistances

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R12 is basically the resistance of the parallel circuit R1 R2 I think

carmine path May 19, 2025, 2:06 AM

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uhhh

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hold up we working on the voltages rn

copper pollen May 19, 2025, 2:06 AM

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Alr

carmine path May 19, 2025, 2:07 AM

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ok ya i think we got it

fallow cosmos May 19, 2025, 2:08 AM

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Yeah i think we’re finished

carmine path May 19, 2025, 2:08 AM

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OK THANKS SO MUCH

copper pollen May 19, 2025, 2:08 AM

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Np

fallow cosmos May 19, 2025, 2:08 AM

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Thank u so much deadass bro

carmine path May 19, 2025, 2:08 AM

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genuienly thank you

sick meteor May 19, 2025, 2:08 AM

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ratgobbler i will never forget you

fallow cosmos May 19, 2025, 2:08 AM

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We wouldve been cooked without u 💔

fallow cosmos May 19, 2025, 2:08 AM

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sick meteor ratgobbler i will never forget you

😭😭😭😭

sick meteor May 19, 2025, 2:08 AM

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you are the chosen one

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all along

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GOATED

carmine path May 19, 2025, 2:08 AM

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i wish u th the best in life

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imma close this now

sick meteor May 19, 2025, 2:08 AM

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happy

carmine path May 19, 2025, 2:08 AM

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+close

patent stagBOT May 19, 2025, 2:08 AM

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carmine path +close

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patent stagBOT May 19, 2025, 2:09 AM

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patent stag

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carmine path May 19, 2025, 2:09 AM

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ratgobbler u deserve the star

#Phsyics Circuit Problem Part 2