I'm stuck after the u-sub of u = (x^2 + 2x)^1/2 du = 2(x+1)/2u dx so i end up with 1/(2(x+1)(x+1)
#help plz :/
vale ocean
forest roostBOT
I'm stuck after the u-sub of u = (x^2 + 2x)^1/2 du = 2(x+1)/2u dx ...
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vale ocean
tall slate
you can split it into partial fractions
vale ocean
you can split it into partial fractions
i dont think that will work
how could i find A and B if theyre the same
willow bridge
I'm stuck after the u-sub of u = (x^2 + 2x)^1/2 du = 2(x+1)/2u dx ...
That's not the way to do it.
Start by completing the square inside the root and making an appropriate substitution based on that.
Oh, although...
willow bridge
Oh, yeah, sorry, I misremembered.
In case of expressions of the form 1/((x - k)^n √(ax^2 + bx + c)) it's better to take u = 1/(x - k). That brings the integral to a nicer form, especially when n = 1.
willow bridge
Yeah, take u = 1/(x + 1).
vale ocean
alr bet bet thx
willow bridge
You're welcome!
Try it out. Just be careful with the substitution, some algebra will be involved.
hollow glade
You can indeed partial fraction this, but you have to solve for $(x+1)^2$ by completing the square inside your subsitution $u=\sqrt{x^2+2x}$.
flat havenBOT
Kocher
hollow glade
Or, this might not be partial fractions. But a common integral regardless.
willow bridge
You can indeed partial fraction this, but you have to solve for $(x+1)^2$ by com...
1/(x + 1) is already a simple fraction.
There's no need.
The standard substitution in this case is u = 1/(x + 1).
balmy shaleBOT
@vale ocean
floral ice
Guys, am I permitted to solve the question for SpiritDome?
willow bridge
Guys, am I permitted to solve the question for SpiritDome?
Well, we've already discussed it. I assume they just forgot to close the post.
hollow glade
Guys, am I permitted to solve the question for SpiritDome?
?tag helping
uneven ermineBOT
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candid prawn
?tag helping
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