#Improper integral
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cus i thought that if x-->infinity then the bottom part is bigger than the top part
therefore it tends to 0
but my thinking is wrong
Well, (2t^2 + 3)^2/(t + 1)^4 for t = 0 is 4.
Oh, wait, it's for infinity.
yeah
No. Why? The orders of both the numerator and denominator are the same (t^4), so just compare the leading coefficients.
everytime i do these type of questions i always mess up when evaluating the integral like here
wait i never done this
so i expand the 2t^2 +3
and compare the 4t^4 with the t^4 on bottom?
ohhhhhhh
ok
so wait if i ever get a question i should divide everything by the highest order of the numerator?
Well, in general, when evaluating the limits of rational functions, you factor out the highest powers from the numerator and denominator, then cancel.
Then you're left with a power of t (in this case t^0, since the degrees of numerator and denominator are the same) and an expression with a finite nonzero limit.
i sort of understand it i think
ima try dividing everything by t^4 and see what happens
1 sec
Just recall how you did it when studying limits.
i think i sort of get it now
all other terms are bascially irrelevant since it goes it infinity and you divide by t
is this a valid way?
my teacher skipped over this part
he thought that we already knew it and never did it
Well, probably better to write the fraction in the last step as (2 + 3/t^2)^2/(1 + 1/t)^4. Still exact, but you can still see the infinitesimal terms.
Oh... Quite an important step to skip.
i see i will keep that in mind next time
yeah need to relearn it rn
but tysm
+close
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