#I HAVE AN EXAM TOMORROW PLS HELP
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what exactly do you need help in tho
it seems like sum of 2 AMs
check the pattern
3+0
6+1
9+2
12+3
15+4
.
.
.
if I am not wrong this should be the pattern
yes but i need a rule
ohh so, let $a_k$ be the $k^{th}$ term in the pattern
Japanese Transformation
that is, for $k=1$ you have exactly 1 black figure
Japanese Transformation
so, $a_k = 3k + (k-1)$
Japanese Transformation
for exactly one black figure, $a_1=3 \cdot 1 + (1-1)) = 3+0 = 3$ so length is 3
Japanese Transformation
for two black figures, $a_2=3 \cdot 2 + (2-1) = 6+1 = 7$ so the length is 7
Japanese Transformation
This is the rule: 4n - 1
so this is to find the total hexagons?
no
4(1) - 1 = 4 - 1 = 3 ...1st one: n = 3
@kindred coral the thing is that, the space between the black figures increases as the number of black figures increase?
but it seems
sum of 2 APs = AP
so yeah
4k - 1 should be the rule indeed
Why did you say no? Please let me know.
I guess that's not what he meant by rule
I went by what I saw based on what he posted: 3 black, 7 black, 11 black...that is an Arithmetic Sequence
ya
uh what
wha
Based on what you posted and what I saw, n = 3 (1st), n = 7 (2nd), n = 11 (3rd);
n is supposed to be how long the figure is
if n=3 then 12-1 = 11 which is giving us 3 black figures
the length of the total pattern
Can you post the "entire" question?

This is what I see on my end
The diagram is not complete.
There should be 7 black parts, and 11 black parts respectively in the 2nd and 3rd diagrams. Do you understand what I mean?
Based on what I saw, I gave you the answer. There are also more examples that I sent to you.
You did not paste the "entire" diagram.
Please check to make sure you posted the entire diagram.
Yep.
You can type +close to close the post.
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You can derive this by calling the shaded ones s and relating the arithmetic sequence of s and n.
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