#SIGMA NOTATION

30 messages · Page 1 of 1 (latest)

void hare
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3+15+35+63...
It's fucking general term is r*(r+2) right?
and using sigma notation i get (2n^3 + 9n^2 + 7n)/6
but the ans is fucking diff idk how

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past mistBOT
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void hare
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1*3 + 3*5 + 5*7 + 7*9 + 9*11 and so on.
general term: r(r+2).
r^2 + 2r
sum of sq of natural numbers till n:
n(n+1)(2n+1)/6 + 6*n(n+1)/6

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bruh

raven phoenix
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What did you get as the formula for the nth term?

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@void hare

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You should’ve gotten ||4n^2 - 1||

void hare
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i alr told u

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i got n(n+2)

raven phoenix
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As the formula for the nth term?

void hare
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n+2*

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sorry not n-2

raven phoenix
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You can just apply that and see that it doesn’t work

void hare
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shit.

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i was so dumb

raven phoenix
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No, at n=2, n(n+2) = 8

void hare
raven phoenix
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The nth term is actually ||(2n-1)(2n+1)|| which is equal to ||4n^2-1||

void hare
raven phoenix
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So, you got it?

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If you did, you can close this thread

void hare
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yea got it

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thank

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+close

rich helmBOT
# void hare +close
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