Drawing isomorphic graphs (Going crazy about the answer provided in the image plz help)

[turbid lily]

Hi, basically I am trying to wrap my head around drawing isomophic graphs, when i was doing this question I really got confused. How can the answer to this questio be so simple? Can someone please explain the answer because i was about to rearrange/redraw all of the diagonal edges. I never thought of drawing the way it is done in the answers. I really am losing my mind like bruh. Someone plz help I feel so ashamed and embarrassed. I don't know what I'm feeling. I just don't know how the answer in the image I have provided can be something simple like that bruh. I don't know how to draw isomorphic graphs anymore at this point. I think the next step forward would be someone to explain me this question before I study more about isomorphic graphs.

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[versed flint]

the graph in the answer satisfies the requirement

and it's clearly isomorphic to the first one

graph isomorphism is a very difficult problem in general, so you wouldn't be the only one

[turbid lily]

can u give me tips when drawing isomophic graphs?

[versed flint]

not really, there isn't any one finite list of things to check other than the definition itself to guarantee isomorphism

the intuitive explanation is, if you can obtain the new graph by stretching/rotating/reflecting the first one

then it's isomorphic

[turbid lily]

ive been doing this by looking at the degree vertexes and the number of edges/vertices etc

[versed flint]

in this case you see the two edge that go from the bottom left to the two top right nodes

these are the ones that cause overlap

so you "stretch" them outside of the box

and obtain the graph given below

[turbid lily]

im allowed to do that?

[versed flint]

why wouldnt you be

[turbid lily]

bruhh

[versed flint]

it's a graph, yes?

[turbid lily]

yes

ok thanks for help

[versed flint]

it's not the only solution either

[turbid lily]

Oh

Ok thanks for helping i think i understand more than i did before sking

asking

[versed flint]

[turbid lily]

+close

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@turbid lily

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[turbid lily]

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