#Calc 1 inverse trig derivative problem

1 messages · Page 1 of 1 (latest)

silver forge
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I found the solution in another way, but the question probably doesn't want me to solve that way lmao. How can I simplify the first attempt? 😭

20250418_201817.jpg 20250418_203158.jpg
patent quiverBOT
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true tangle
silver forge
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i think it wants me to use the actual derivative

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like i did in the first img (used chain rule to get -sin u *du/dx , where du/dx = 1/√(1-x^2) and u=arcsin x)

true tangle
silver forge
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sorry if I wasnt clear, the question wants me to prove cos (arcsin x) =√(1-x^2) using derivatives

true tangle
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Then... differentiate them both.

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The idea is that if df/dx = dg/dx, then f(x) = g(x) + c.

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Per the fundamental theorem of calculus.

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Or probably some lesser theorem.

silver forge
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ohh

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okay I solved the answer properly

silver forge
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+close

sterile valeBOT
# silver forge +close
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sterile valeBOT
# sterile vale

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