#Find alpha
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I found gradient of both tangents
But then apparent'y I'm supposed to use some tan inverse thing that i dont understand
idk if you are given the formula
but where im from we get a formula sheet
its like tan(angle) = |m2-m1/1+m1m2|
so you find derivative of both curves
sub in x = 4
and since the derivative is js gradient
then u sub it into that
What i was told is subtract tan inverse of 3 from tan inverse of 1/2 which are the 2 gradients of the 2 lines
is the answer 45deg
We don't get that formula
ah
i can show u how i did it
but idk how they did it
i js found derivatives and stuff
ifykwim
so first find derivative of both of the curves
yea pretty much
normally the questions ive seen like this are 2-3 marks
2 marks for finding the derivatives and subbing in the correct x value
and the finla mark for solving for the angle
final*
i dont know why they have done that
search up angle between curves formula
idk i had it on my formula sheet last year
Find the derivatives of both functions at x=4
As a first step
So what are they
1/sqrt(x) and x-1
yeah and get 1/2, and 3
Alright
So these happen to be positive
So to get the angle between each tangent and the x axis
We can just arctan each slope
,calc arctan(3)
The following error occured while calculating:
Error: Undefined function arctan
,calc atan(3)
Result:
1.2490457723983
,calc atan(1/2)
Result:
0.46364760900081
why does that even work tho
If you think about it for a moment
The slope of a line is just the ratio of the rise over the run
Which is just opposite/adjacent
Anyway so our alpha is
,calc atan(3)-atan(1/2)
ohhhh
,calc atan(3)-atan(1/2)
Result:
0.78539816339745
alr ty
Convert to degrees if needed
Close channel
from this thing
oh ok
Then you'll get the option to
+close
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