#please help me solve this question
25 messages · Page 1 of 1 (latest)
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Have you tried rationalizing the denominator of the left hand side?
yes i have but i keep getting x^4= 5/4
Show your work.
you should try multiply both the numerator and the denominator to the conjugate of the denominator ( as in like (a+b)(a-b) = a^2 - b^2, so you multiply them with (sqrt(x^2 + 1) + sqrt(x^2 -1)) so the denominator turns into (sqrt(x^2+1))^2 - (sqrt(x^2-1))^2 which simplifies into (x^2+1)-(x^2-1), which is just 2. sorry if writing using keyboards characters is confusing, i can show a paper writen veresion with explaination but i need to check the rules for this server, also eng isnt my language so excuse me for that
I already explained this.
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yes thank you for reminding me the rules here! i just wanted to specifies exactly on how to do so (rationalizing) incase OP isnt sure on how to do so.
Wait, are you referencing that $\varphi=\frac{1+\sqrt 5}{2}$? In that case, that isn’t the answer. In fact, there are no real solutions.
Kocher
instead of rationalising i used componendo and dividendo first
ultimately the answer i got was x²=√5/2
however this value of x² didnt satisfy the equation
so does this automatically mean that it doesnt have a real solution or do i need to solve further?
Yes, it means it doesn’t have a real solution.
Do you have the textbook’s solution (not the answer)?
no there is no solution for the question
there's only answer keys
but anyways thanks
yeah this would be $\pm\frac{i\sqrt[4]{5}}{\sqrt{2}}$
ooaa
@quartz coyote
Hello third_tooth, this is a friendly reminder that your help request has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command. This thread will be automatically closed in 3 days if it remains inactive.