I have an exam in 3 hours pls help

[karmic harbor]

okay so i dont get this whole page...

i have a list of formulas and stuff but im going to crash out cause idk what to use and why

im studying rn but legit this page is kicking my ass 😔

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[blissful vapor]

@karmic harbor is there anything in particular you are struggling with that we could start with?

[karmic harbor]

i dont get 8b 😭 or 8 in general ik that i can turn 8a to y=2x+5 and then do m1xm2=-1 which makes m2= -1/2 but i dont get the second one

like at all

idk where to start even

[blissful vapor]

Do you know what type of function is being described?

[karmic harbor]

i have no clue wtf is going on i just know theyre looking for a slope whatever

[blissful vapor]

The type of function they're describing there is a parametric function

Because your variables depend on a third parameter λ

[karmic harbor]

okay that sounds more familair

[blissful vapor]

Rather than a relationship of x and y like usual

Yes that's good

If you want to get rid of the λ and express it as a relationship of x and y then all you have to do is solve for λ on both sides and set them equal

And it's gone

[karmic harbor]

the ecuation i have written down for parametric is

x= P1 + t x V1

y= P2 + t x V2

i guessing that symbol is the replacement for t

and its at the end cause its being multiplied

[blissful vapor]

Ye

[karmic harbor]

this is the answer of a friend of mine idk if shes wrong or if im confused

idk how she got that as her answer

[blissful vapor]

Oh wait yeah that's a much better way

So basically what she's noticing is that (x, y) expressed as a vector would be:

(x, y) = (2, 1) + (5, -3)*λ

So it would look like a line with its start on the point (2, 1) and and along the vector (5, -3)

So your slope is the line v = (5, -3)

And you want a line parallel to (5, -3) but going through (4, 1) instead of (2, 1)

So now you have a point and a slope and can express it in terms of many ways

[sacred flint]

¡Buena suerte!

[karmic harbor]

es una mierda 😔

he tenido el examen esta mañana y lo he cargado

[sacred flint]

You’ll be fine lol

Los vectores son fáciles si sabes los líneas y los planos de 3D, como $\frac{x-a}{x_1}=\frac{y-b}{y_1}=\frac{z-c}{z_1}$ y $Ax+By+Cz+D=0$

[indigo path]

Kocher

[sacred flint]

Parametric form is setting the former equal to t

The latter is the general form of a plane

Usa estes formas de los vectores en general, o usa $\mathcal{L}=\begin{pmatrix}a\b\c\end{pmatrix}+t\begin{pmatrix}x_1\x_2\x_3\end{pmatrix}$ por una línea $\mathcal{L}$

[indigo path]

Kocher

[sacred flint]

If this is too much information let me know

It’s similar to 2D, just let all the z-components equal to 0

[trail spruce]

@karmic harbor

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[karmic harbor]

+close

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