#proof is a norm

16 messages · Page 1 of 1 (latest)

grave yarrow
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I need help to prove $\lVert f\rVert := (f(a)^4+f(b)^4)^{1/4}$ is a norm on X where is the set of monotone functions on the interval [a,b]. I'm stuck with the triangle inequality and they gave us a hint to use $h(t) = (1+t^4)^{1/4}-1-t$ for t>0 and not use norm 4 on R2. any help?

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vale zealot
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$$1+t^4 \leqslant (1+t)^4$$

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vale zealot
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the function h is nonpositive for t > 0

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your goal is to show

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$$|f+g| = \left ( (f+g)(a)^4 + (f+g)(b)^4 \right)^{1/4} \leqslant \left ( f(a)^4 + f(b)^4 \right)^{1/4} + \left ( g(a)^4 + g(b)^4 \right)^{1/4}$$

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vale zealot
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do some algebraic manipulation and you'll get it

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@grave yarrow

grave yarrow
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actually there was a mistake and they changed the question -
X is the sub-space of C([a,b]) spanned by $cos(\frac{\pi}{b-a}\cdot (x-a))$ and $\frac{3}{b-a}(x-a)-1$ and then the rest is ok

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balmy walrusBOT
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@grave yarrow

:HelpIcon:| Help Reminder

Hello meitar5674, this is a friendly reminder that your help request has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command. This thread will be automatically closed in 3 days if it remains inactive.

vale zealot
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@grave yarrowclose the topic