#1015578016606343218
#HELP!!!!!!!DETERMINE WHEN THE IRRATIONAL FUNCTION IS DEFINED
small swallow
silent plankBOT
<#1015578016606343218>
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stoic sigil
<#1015578016606343218>
...so... do that.
small swallow
You're not helping me, I said help
stoic sigil
You're not helping me, I said help
Oh, you're rude and lazy. Okay, bye.
stoic sigil
Stop being rude and lazy.
stoic sigil
It sounds like you need a break.
stoic sigil
Of course it's wrong, you did a bunch of random nonsense.
stoic sigil
This is very simple.
small swallow
You're so condescending
stoic sigil
When is sqrt(x) a real number?
small swallow
When its > or equal to 0
stoic sigil
...no, negative numbers are also real numbers.
small swallow
Yes but I can't do that under the square thingy
stoic sigil
You need. To be. Precise.
stoic sigil
What you said is that sqrt(x) is real when sqrt(x) >= 0.
stoic sigil
Except if sqrt(x) < 0 it would still be real.
stoic sigil
The answer to the question I asked is that sqrt(x) is a real number when x is nonnegative, i.e. x >= 0.
stoic sigil
Therefore, when is sqrt(-x^2 - 3 sqrt(2)) a real number?
stoic sigil
What I said basically
No it's not.
small swallow
If can't be in R because x² is a negative number
stoic sigil
What you *said* is that `sqrt(x)` is real when `sqrt(x) >= 0`.
@small swallow This is what you said.
stoic sigil
If can't be in R because x² is a negative number
Stop saying "it".
small swallow
No it's not.
You're very childish right now
stoic sigil
You are no longer allowed to use the word "it".
stoic sigil
You're very childish right now
Rude and lazy.
small swallow
I accidentally wrote if I didn't even right it
small swallow
Rude and lazy.
Girl
You should look at yourself
Cause you're not helping me
Now do me the 2 exercise
stoic sigil
I'm trying to help you, but you're too rude and lazy.
stoic sigil
Now do me the 2 exercise
What does this even mean?
stoic sigil
...yes, that's the part I understood.
small swallow
I don't understand the second exercise
stoic sigil
Clearly.
small swallow
How do I resolve it
stoic sigil
By paying attention and answering the questions I ask.
small swallow
Ok fo what you have to do
stoic sigil
And not insulting me.
small swallow
Ok I can do that
stoic sigil
Can you? You've consistently failed at both tasks so far.
small swallow
I'm sorry
stoic sigil
I don't believe you are but I don't care enough to prosecute it.
So when is sqrt(x) a real number?
small swallow
YOU TOLD ME IT WAS WRONG
swift shore
Techie Literate is clearly illiterate.
spark bridge
we know that the square root of a function where x is a an element of all real numbers is always greater than or equal to 0
so set f(x) greater than or equal to 0 and isolate for x to find the interval
$\sqrt{-x^2-3\sqrt{2}}\ge 0$
flat finchBOT
SpiralShape21
spark bridge
for 258
stoic sigil
we know that the square root of a function where x is a an element of all real n...
That's not the problem, though.
spark bridge
That's not the problem, though.
Wait I thought it was asking when the function is defined. Aren't we just finding the domain?
stoic sigil
Wait I thought it was asking when the function is defined. Aren't we just findin...
...yes. Which is... exactly why you're on the wrong track.
spark bridge
What's the right track?
stoic sigil
What's the right track?
The one I tried to start OP down five times, the one I'd be done with by now if they listened to me.
spark bridge
Maybe I'm missing something, but I don't understand what's wrong with my solution.
Cuz you end up with $x^2 \le -3\sqrt{2}$
flat finchBOT
SpiralShape21
spark bridge
So there are no x values that satisfy the conditions
At least no real values
So there's no real domain, which is the answer
stoic sigil
Cuz you end up with $x^2 \le -3\sqrt{2}$
No you don't.
small swallow
You guys are all useless, I had that EXACT same exercise and I wasn't able to answer it
Be ashamed
small swallow
No you don't.
Techie literate more like TECHIE ILLITTERATE
spark bridge
You guys are all useless, I had that EXACT same exercise and I wasn't able to an...
Sorry. What about the question are you having trouble understanding?
slim elbow
Okay. @small swallow , not the nicest way to deal with a helper. If they’ve tried something again and again, and it doesn’t work out for you, it’s likely that they’re more upset than you are. @stoic sigil, I know you’re upset and are trying to prove a point, and I understand where you’re coming from, but the same sort of mutual respect applies here as it does to the helpee. Being condescending just snowballs the entire conversation and leads it off track from what it should be. Both of you, in the future, please be kinder.
Also, whoever tries to instigate or make the argument worse, you’re going to get punishment. All you’re doing to the conversation is fueling the fire, nothing more. Take this as a verbal warning as well. And if you feel there is an issue, feel free to ping helper moderators.
stoic sigil
Okay. <@951534176715301024> , not the nicest way to deal with a helper. If they’...
This helpee has been consistently disrespectful from literally the first message, and I gave them several chances not to be.
obsidian mortar
You were both consistently disrespectful off the bat
slim elbow
@small swallow Do you still require help?
small swallow
Other than mental help and comfort from the traumatising experience I still want to know how to do the 2nd exercise
No jokes but you guys are so kind helping others 😞♥️ ily all especially you Teckie, I hope we can be friends if you are willing to forgive me 💖
ember yarrow
this is so weird lmao
u have to find when x is positive, because there arent square roots for negative numbers
so, you have to solve the inequality $$x^2-5 \sqrt 2 x +12>0$$
flat finchBOT
roi
ember yarrow
it solves like a normal quadratic, except for the final step
try solving it and lmk if you have any questions
obsidian mortar
so, you have to solve the inequality $$x^2-5 \sqrt 2 x +12>0$$
= not just >
warm abyss
Oh, you're rude *and* lazy. Okay, bye.
Being rude by wanted help not to be told to 'just solve it'
slim elbow
Other than mental help and comfort *from the traumatising experience* I still wa...
In general, you just want to follow what Techie said earlier. Namely, first find when the argument of the (irrational) function allows for real outputs, then configure the argument in such a way that this is possible.
The argument (what I am referencing to) is g(x) in f(g(x)), where f is the function we are analyzing.
knotty pelican
You're very childish right now
No he wasn't, he was trying to teach you to be more rigorous in your ways of thinking, which was quite sloppy. If you want to excel in math, that's the mode of thinking you should be in, but it feels more like you're just looking to pass your exam or homework and get it over with.
knotty pelican
Okay. <@951534176715301024> , not the nicest way to deal with a helper. If they’...
I personally thought Technie was okay to be honest. He was just trying to help them think for themselves instead of spoon-feeding the answer to them (which is how real learning occurs IMO).
wise anvil
this is es
clear veldtBOT
@small swallow