#Maclaurin Series

1 messages · Page 1 of 1 (latest)

grave maple
#

I don't understand what I did wrong i got 3/4 as an answer and the answer model got -3. they divided by
x^2 first and then filled in x = pi/2, i just can't see why what i did is "wrong" (filling in x = pi and then factoring out 4 pi squared). Someone help please.

Oh it's question 9b by the way

woeful caveBOT
#
  1. Do not ping the Moderators, unless someone is breaking the rules.
  2. Do not ping the Helper Moderators, unless there is a conflict between helpers.
  3. Do not ping other members randomly for help.
  4. Ask your question and show the work you've done so far. If you've posted a screenshot of a question, specify which part you need help with.
  5. Wait patiently for a helper to come along.
  6. If the Helper has answered your question, remember to thank them with the Mathematics Ranks bot and close the thread with:

+close
Feel free to nominate the person for helper of the week in #helper-nominations
If you're happy with the help you got here, and the server overall, you can contribute financially as well:

rigid moss
#

(-4)^k doesn't become 4 (-1)^k, but 4^k (-1)^k

#

Here it would be more practical to rewrite the sum as:
$$f'(x) = x^2 \sum_{k=0}^{\infty} (-1)^k \frac{2k+3}{(2k)!} \left( 2x\right)^{2k}$$

wheat bisonBOT
#

Miguel

grave maple
#

I was wondering where that 4 went in the answer model

#

still am actually. where did it go?

rigid moss
#

see that (2x)^2k I wrote?

#

they just replaced the 2x with pi

#

in other words they subbed x = pi/2

grave maple
#

wow they skipped so many steps inbetween hahahah thank you!

rigid moss
humble jacinthBOT
#

@grave maple

:HelpIcon:| Help Reminder

Hello .endless.void_, this is a friendly reminder that your help request has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command. This thread will be automatically closed in 3 days if it remains inactive.