#vectors

55 messages · Page 1 of 1 (latest)

civic canopy
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Hi! I need help with b.
Thanks in advance!

civic wingBOT
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tawdry mountain
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You took the dot product, right?

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Hint: Properties of quadrilaterals come into play.

civic canopy
civic canopy
tawdry mountain
tawdry mountain
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Well, we know BC || AD.

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So what does that tell us about ABCD?

civic canopy
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or wait

civic canopy
civic canopy
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i know that they are parallel but if the length of then aren’t the same then it might not be parallelogram

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right?

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or am i wrong

tawdry mountain
civic canopy
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aaah

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for part a i got 4

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so they are equal

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so now i know that three sides have the length that equals to four which means that the last one would also equal to 4, so DC

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so it could have been a parallelogram but since all the sides are equal then i would say its a rhombus maybe

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a parallelogram would have two equal sides and the two other would also equal each other - so for instance 2y sides and 2x sides where the angle is not equal to 90

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however i am not sure if my conclusion would be correct..

civic canopy
tawdry mountain
civic canopy
tawdry mountain
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And also, consider the angles that a rhombus/parallelogram has.

civic canopy
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i would say that BA is for instance -vector a

tawdry mountain
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Yes.

civic canopy
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-a

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and BC would be b

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a*b would equal to -8

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and so i dont understand why -a*b would equal to 8

tawdry mountain
civic canopy
tawdry mountain
civic canopy
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i would have just done it like this

civic canopy
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ohh i drew it incorrectly - i wrote C where i wanted to write D

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so the calculation doesn’t make any sense

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now its correct i think

civic canopy
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alsoo, i need help with g

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@scenic cliff

normal raptor
# civic canopy Hi! I need help with b. Thanks in advance!

g) $\vec{BP}=\frac12\vec{BD}=\frac12(0\vec{i}-4\sqrt{3}\vec{j})=-2\sqrt{3}\vec{j}$\
since $AC=4\vec{i}$, and we know that $BD$ and $AC$ are perpendicular, we must prove that $k=\frac12$ for $\vec{AP}=k\vec{AC}$\
we can do this with the dot product and thus since $\vec{AC}\cdot\vec{BD}=0$, we have $2\vec{BP}\cdot \frac1k\vec{AP}=0$ and thus $0\times 4-2\sqrt{3}\times 0=0$, so they are indeed perpendicular as well and thus $k=\frac12$

rugged plazaBOT
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vengeance

nimble raftBOT
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@civic canopy

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civic canopy
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+close

nimble raftBOT
# civic canopy +close
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