#Can someone help me with this question plsssss
138 messages · Page 1 of 1 (latest)
- Do not ping the Moderators, unless someone is breaking the rules.
- Do not ping the Helper Moderators, unless there is a conflict between helpers.
- Do not ping other members randomly for help.
- Ask your question and show the work you've done so far. If you've posted a screenshot of a question, specify which part you need help with.
- Wait patiently for a helper to come along.
- If the Helper has answered your question, remember to thank them with the Mathematics Ranks bot and close the thread with:
+close
Feel free to nominate the person for helper of the week in #helper-nominations
If you're happy with the help you got here, and the server overall, you can contribute financially as well:
ye but...we don't know the weight?
idk it's just any units ig
and we don't know the density
it's meant to be a math question, so i don't think we will have to use a phy topic. There has to be a math way?
@austere vortex
<@&1309522179368419349>
I know what the volume of the cuboid is - 10x^2
And the volume of the water = volume of cylinder tank up to 10 units - volume of the cuboid
So, 3600-10x^2
This is all when the square face of the cuboid is touching the cylinder’s bottom surface
And this is orientation 1
Now orientation 2 is when the rectangular face of the cuboid is touching the cylinder’s bottom surface
But now the water level drops by one unit which suggests that not all of the cuboid is submerged in the water
@pure bobcat the water level does not drop further
@pure bobcat my calculations shows that it drops 0 level
Can I see it?
That can’t be right because if you take the cuboid out then the water level should decrease as a result of decreased volume
The volume of the box and squared base is the same
Sorry, I was studying
I'm a bit tired right now but I'm trying to comprehend the problem
Np
The volume of the square based cuboid is 10x^2, right?
some of the box is peeking out
that’s what is happening
and you need to find the height of the cylinder thingy
ohh ye i thought abt it
since it is some of the cuboid is not fully submerged in the water, x has to be greater than 10?
doesn’t have to be i don’t think
i can’t really know because
the submerged area also changes
when you flip
so i don’t think it’s necessarily that
i’d just try another way of solving
hmmm
we know an expression for the volume of the water tho
I know what the volume of the cuboid is - 10x^2
And the volume of the water = volume of cylinder tank up to 10 units - volume of the cuboid
So, 3600-10x^2
This is all when the square face of the cuboid is touching the cylinder’s bottom surface
And this is orientation 1
Now orientation 2 is when the rectangular face of the cuboid is touching the cylinder’s bottom surface
But now the water level drops by one unit which suggests that not all of the cuboid is submerged in the water
i would caution saying the cylinder container has height 10
unless i’ve misread a question again 🤣
no?
the cuboid has height 10
ahh 3600 is the volume of the cylinder upto the height 10
ah ok
bcuz that's where the water is filled upto
oh is it implying water is added so it reaches the top of the cuboid
that’s so stupid
yes
they could’ve said that in the question 0/10 question design
'When the box is in the tank of water with a square face against the bottom of the tank, the water reaches the top of the box.'
👍
well then yk how much volume happens when the water level lowers
so try making an equation for that
i think that solves? idk if more conplications arise
idk either
i tried to set the volume of the water equal to each other
so, 3600-10x^2 = 360(9)-10x^2
but that doesn't make any sense
so im confused
try picturing the prism again from the rectnaglular base
and the figure out length width height
@charred thicket
cuboid
It still has the same dimensions, because the box doesn’t change when u change the orientation
It says in the q
if the top isn’t submerged
ohh u mean the volume of the cuboid which is submerged?
ahh i get it now
i thought u were just asking for the volume as a whole
mb
then the height is gonna be x-9?
and the other dimensions are the same
wdym?
that’s the height outside of the water
you want the part od the block pushing the water up
900x?
is the volume of the cuboid that is submerged in water
so the volume of the water is 360(9)-900x?
and that is equal to 3600-10x^2, because these are the two expressions for the volume of the water.
ye
am i on the right track?
yes
we don't have to solve for x do we?
decently sure that solves it unless more weird stuff occurs
😭
might ve a faster way
but in any test environment i’d just grind out the x solve
hm
nvm i made a mistake, x is NOT irrational 😭
i put 900x instead of 90x 💀
yay
i think i can solve it from here, meanwhile can you please look at https://discord.com/channels/624314920158232616/1352000285244919879 if you have time
respond to kocher smh
oh he replied
i thought no one did
kk i'll respond to him after im done
i'll send it to u when im done
tysm @charred thicket
@pure bobcat
Hello stem369, this is a friendly reminder that your help request has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command. This thread will be automatically closed in 3 days if it remains inactive.
