#How is this incorrect? I found the pentagon area and then multiplied by the height?

111 messages · Page 1 of 1 (latest)

nova temple
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I got 0.22579 as the apothem and 17.5 as the perimeter and once you multiply those together and divide it by 2, you get the area of the pentagon which is 1.975686 and then you multiply that by the height, 9, and that's how I rounded to the nearest tenth and got 17.8

stone tendonBOT
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limpid narwhal
nova temple
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Huh?

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The area of a pentagon is 1/2 ( apothem x perimeter )

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Not whatever that is

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Area of a prism = Bh ( B = area of base )

limpid narwhal
nova temple
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What does it mean to triangulate

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I'm trying to get the figure on screen

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Not a triangle

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Do you want me to go step by step and you can see where I messed up?

limpid narwhal
nova temple
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Yeah that's what I did

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Okay so

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We know the Volume of a prism is Bh

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Pentagon Area = 1/2(apothem x perimeter )

limpid narwhal
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If by B you mean the area of the base, then yes.

nova temple
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Yeah

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So I split the pentagon into 5 triangles

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Then split one of the triangles to get this figure

limpid narwhal
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Right.

nova temple
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Each inscribed angle is 72 but since we cut it to find the apothem, it's half

limpid narwhal
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Yes.

nova temple
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The perimeter of each side is 3.5/2 is 1.75

limpid narwhal
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Well, length, not perimeter.

nova temple
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Then I did the tan(36)=1.75/x

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Yeah

limpid narwhal
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Right.

nova temple
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and then I multipled both sides by x

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to get x(tan(36))=1.75

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then divded to get x=1.75/tan(36)

limpid narwhal
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Fine so far, though you missed the units and the degree sign.

nova temple
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Those aren't needed rn right?

limpid narwhal
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If you want to use values, which you generally shouldn't do, they are always needed.

nova temple
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Oh okay

limpid narwhal
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Better to solve this as usual - generally.

nova temple
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I plugged this into my calc

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and got this

limpid narwhal
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No, wait.

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That's not a good idea.

nova temple
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Wdym

limpid narwhal
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Don't do any intermediate calculations.

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That introduces error.

nova temple
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So I should keep it as is?

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1.75/tan(36)

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For the apothem

limpid narwhal
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Yes.

nova temple
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Okay

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So

limpid narwhal
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Oh, hold up.

limpid narwhal
# nova temple

That isn't correct. You forgot the degree sign, and that affected the answer.

nova temple
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Oh I don't have to do that with my hand held calculator

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I used a random one online

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Let me get my hand held and see if I get the same answer

limpid narwhal
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Then use radians.

nova temple
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Oh

limpid narwhal
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Anyway, that's for later.

nova temple
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I failed the radians unit

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I wasn't here the entire unit

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No idea how to do it

limpid narwhal
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The apothem has length x = a/(2tan(π/5)). What next?

nova temple
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I thought it was 1.75/tan(36)

limpid narwhal
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Yes. Which is a/(2tan(π/5)) for a = 3.5 in.

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And with the correct angular units.

nova temple
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Oh shoot on my Ti84 I got 2.40866

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Way different than what was on the website

limpid narwhal
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Yes, that will be right. Though, we don't need that value right now.

nova temple
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ok

limpid narwhal
nova temple
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So 1.75/tan(36) x 17.5

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Is the area of the pentagon

limpid narwhal
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Yes, 5a^2/(4tan(π/5)). That's the area of the base.

nova temple
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Then multiply that by 9

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For the prism

limpid narwhal
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Right. So, V = 5a^2 h/(4tan(π/5)).

nova temple
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Then divide by 2

limpid narwhal
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No, why?

nova temple
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I forgot to divide by 2 earlier

limpid narwhal
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Ah. Yeah.

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See, that's why it's better to solve generally.

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Just numbers won't show where you made a mistake.

nova temple
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What step did I forget to divide by 2

limpid narwhal
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That's what I'm talking about.

limpid narwhal
nova temple
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The area of a pentagon is 1/2(perimeter)(apothem)

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ah

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so that divided by 2 gives us 189.7 rounded to the tenths place

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Okay so in general I just made a calculator mistake.

limpid narwhal
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Well, yeah, the degrees problem was the most important one.

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And, again, you should solve problems generally, if possible.

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Do you want me to show how I'd write it?

nova temple
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I know how to write them

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It's just akward

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To write such big equations that I can js solve

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But I get the reason why

limpid narwhal
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I mean how to write it properly.

nova temple
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Oh, sure! I'd like a little lesson.

limpid narwhal
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Anyway, like this.
V(prism) = S(base)h
S(base) = (1/2)P(base)x = (5/2)ax = (5/2)a*(a cot(π/5)/2) = (5/4)a^2 cot(π/5)
V(prism) = (5/4)a^2 h cot(π/5) = (5/4)(3.5 in)^2*(9 in)*cot(π/5) = 189.7 in^2

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So, the approach for solving most math, physics and chemistry problems is the following:

  1. Introduce variables for the given quantities and for what you need to find.
  2. Derive the formula for what you need to find in terms of what you're given.
  3. Subsitute the values of given quantities.
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Note that we don't do any intermediate calculations. At least, when possible.

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That way we don't introduce rounding errors.

nova temple
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ooh okay

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Sorry I was doing something but I had to read it for a sec

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I'll try to do this so I don't have to round my problerms

limpid narwhal
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Alright, nice!

whole anchorBOT
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@nova temple

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