#Trigonometry homework
17 messages · Page 1 of 1 (latest)
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okay update, ive got the first page and now i need the second one only
For the triangles in the first picture, take note of what sides are known with respect to the angle. And recall the definitions of trigonometric ratios:
sin(x) = (opposite side)/(hypotenuse)
cos(x) = (adjacent side)/(hypotenuse)
tan(x) = sin(x)/cos(x) = (opposite side)/(adjacent side)
Ah, ok.
In the second picture:
- Recall that the height dropped onto the base of an isosceles triangle is also a median.
- Find one of the angles of the triangle ADC, for example, and then see how you can get to the needed angle.
- Note that the needed angle is the different of angles BAD and BAC.
would this be a correct way of solving tge problem with an isosceles triangle with a side of 14 and a bottom side of 10 as a whole? I have found that 10 / 2 is 5, and since both of the sides are the same, i wrote 14 on one and pretended the other 14 was there. I then marked the unknown angle (x) and marked the right angle from the dotted line to find the hypotenuse. I then entered cos ^-1 ( 5 over 14 ) and got 69.07516757 which rounds up to 69 as the nearest whole number
Well, arccos(5/14) is approximately 69° (don't forget the degrees sign, by the way). Also, that's rounding down (or just rounding), not rounding up.
The approach is correct.
wait so in a more simply put way, how could i answer this question? i’m so tired my brain is boiled 😢
Do you know what vertical and supplementary angles are?
yeah, i did it sorry for not updating !! thank you to both of you 
Oh, alright, nice. You're welcome!
@karmic yew
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