#Rectangle

44 messages · Page 1 of 1 (latest)

tulip frost
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Find the ratio of the area of the shaded region to the area of the rectangle.
O – the intersection of the diagonals of this rectangle.

blazing pecanBOT
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fringe verge
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what are ABCD?

tulip frost
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i tried to do like this. I picked triangles with same areas

fringe verge
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arbitrary points?

lean mortar
fringe verge
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but i assume AB=CD right

lean mortar
lean mortar
fringe verge
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oh true

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alr you got this cook 🔥

tulip frost
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these are same. So from 2 of this kind of triangles both are shaded. so 2/2.

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from 4 triangles that got same area 2 are shaded. which is 2/4

lean mortar
tulip frost
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and from 2 last (small) triangles 1 is shaded which is 1/2.

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so 1/2 + 2/4 + 1 = 2

lean mortar
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So, what's the shaded fraction?

tulip frost
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but this is not correct

tulip frost
lean mortar
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Suppose the whole rectangle has area 1.

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What is the area of the two side triangles?

tulip frost
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0.25

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cuz diogonals divide rectangle into 4 equal triangles.

lean mortar
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Well, 1/4, yeah.

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So, their total area is 1/2.

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Now, let's get rid of them both. What's the total remaining area?

tulip frost
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oh i got your point

lean mortar
lean mortar
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So, it's not 1/2 + 2/4, but 1/2 + (2/4)(1/2), rather.

tulip frost
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wait

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remaining is 0.5 so whats not.

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now we got 2 triangles. each is 0.25

lean mortar
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The approach you can use here is just to use symmetry.

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Here's the rectangle with the side triangles cut out.

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Can you see that the white and gray parts are the same, just inverted around the center?

tulip frost
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ooooooooohhhh

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so it will be 0.25 + 0.5

lean mortar
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Yeah, exactly!

tulip frost
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+close

raw tuskBOT
# tulip frost +close
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raw tuskBOT
# raw tusk

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