#Combinations + Permutations
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I’m assuming that combinations would be used in this case
Okay. Do you know how combinations work?
Yeah it’s the amount of different ways something can be chosen
Good. So what do you think you should do here, as a strategy?
(Note that we want to choose at least one of each game.)
Need atleast one type so u can have either 1 word game, 1 quiz and the rest saga or other way round for all three
But not sure how to put this into a formula where all situations are considered
Okay.
You know about the permutation and combination functions?
Okay.
Well, to be concise, it basically chooses the amount of something (k) out of the possible amount you have (n).
Permutations have order matter, and combinations don't.
Yeah I understand that part but how would you order it in a way where there’s atleast one of each type
You combine possibilites using addition.
So you’d combine the possibility of every single combination there is?
Not necessarily.
Note that we only need 5 apps.
So, we already have 3 spots taken up.
Ohh
Thus, 2 spots remain. Correct?
Yeah
You think you can finish this one on your own?
No
There's really only 2 cases here.
2 spots left
That's alright, then.
And what function should we use? Permutation or combination?
Combination
Good.
For the quizzes, yes.
Explain why.
One quiz is already been used where one of each was required
So 4 left to choose from
And you can have 2 from the 4 or 1 from the remaining 4
But would you times it or add it?
Well, let's split this problem into cases first, to not confuse ourselves.
2 cases:
- 2 apps of the same type
- 1 app of each type, which has 3 possible combinations.
So, can you work out the possibilities for the first case?
Yep.
Okay, here is a hint for the second; when dealing with the pairs themselves, multiply the possibilities.
So 15c1 * 4c1 ?
Don’t really understand that part
Which?
How 1 app of each type means 15c1 * 4c1 + 4c1 * 1c1 + 1c1 * 15c1
Hmm. Well, you have different types of phone apps (supposedely), so one isn't necessarily the same as the other. Thus, you need to multiply the possibilities.
Ok so is this part correct?
Since we have 4 apps for quizzes, and 15 for saga games, there are (supposedly) different types of each. So (denoting the n-th quiz game to be Q_n, and the n-th saga game to be S_n), Q_1 and S_1, Q_1 and S_2...Q_2 and S_1...Q_4 and S_15 are all different pairings. This is equivalent to 4*15=60, as we calculated earlier.
Yes.
So there are 60 different ways of having one saga and one quizz app right
Yep.
So now, add all those possibilites together.
These.
This, and the other 2.
This part
191 possibilities of having either 2 types of the same type and 1 type of 2 different types ?
Hmm.
,w 15C2+4C2+1
...
Lol
That’s 112
Yeah.
Yes, according to my calculations.
Oh, isn't this the type of question for which stars and bars are useful?
So now just need to find out how many possibilities of there being 1 type of each
Stars and bars?
Explain please it might help me a lot
What do you mean?
Sound useful
There needs to be atleast one of each type of game
Their installing 5 apps
Yes.
Yeah, a combinatorial method for solving equations of the form x(1) + ... + x(k) = n, where all x-s and n are natural numbers. Two main cases are all x-s being positive (so, your case, pretty much) and all of them being nonnegative.
https://en.wikipedia.org/wiki/Stars_and_bars_(combinatorics)
In combinatorics, stars and bars (also called "sticks and stones", "balls and bars", and "dots and dividers") is a graphical aid for deriving certain combinatorial theorems. It can be used to solve a variety of counting problems, such as how many ways there are to put n indistinguishable balls into k distinguishable bins. The solution to this pa...
Aha. So you add that as well.
Yeah but how would you work that out
Ah, you're right. Sorry.
Wdym by x-s mean and what is n?
Yeah, my bad.
n is the right hand side of the equation, and x(1), ..., x(k) are variables.
Is it supposed to be (2C1 * 5C1 * 16C1) + 191?
Yes.
I don’t really understand it from the Wikipedia link, is there a simple way of putting the stars and bars method?
Ok thanks
You just need the formulas, really.
Would they work for these questions too?
Ah, although, hold on...
Actually, I don't think the usual formulas will work here, since we only have a limited number of each type of object.
Well, there might be a way to generalize this, but I can't say I remember how to do that.
Would u be able to help me with question 16 ii please
This could help.
https://math.stackexchange.com/a/554237
Oh, easy enough: find the number of arrangements of 9 cars, then multiply that by the number of options to place three consecutive empty spaces.
Also with binomial distribution how do you know when to use it rather than condition probability?
Not really sure how exactly those two are related.
Binomial distribution is used when you have n independent trials with the same probability of success p. Then the amount of successes is a random variable X ~ Bin(n, p).
Alright thanks
Also have another question about a different topic should i create a new thread?
what book is this from, just curious i feel like ive seen it before
OCR additional maths
How was it
so glad it didnt come up thay much in my exam
Do u understand it now?
easy
I’m going through that struggle rn lol
nah, not too much but im doing it in furtherpure 2
so il have to learn it eventually
What other topics did u find hard for it
just perms and combs
Have my mock paper tomorrow
Alright thanks
Need to go over that
Yeah I’m decent at that id say
Can u do most of the stuff that’s on the paper w Casio cg50
Trig equations u can do it on that
i didnt have one at the time
ye
its useful but i use CAST diagrams
Was just gonna have a look now
What’s this?
so
il send u a video, its really good for finding all values
i use it instead of the calc ngl
Dyk anything else that I can use cg50 for apart from solveN function and graphs
For trig?
This is a quick demonstration of how to use the CAST diagram to find all the potential solutions to a trigonometric equation. There is a video with a more complete explanation in the A Level playlist for pure maths.
ye
for sine cos tan
hmm lemme think
i use the small one more
fx991 or something
i forgot
white back
like cg50 i only use for graphs il be real
What’s the point of this if u can just put it into the calculator tho?
Of the cast diagram
i dont know if it does, i dont use calc
Oh ok seems abit too long to learn rn tho icl
yea, u prolly wanna focus on ur weaknesses
or stuff u dont remmber as much
u remember ur trig identities?
Is this just using logs to get it into the form y=mx + c
idk man alevel is boring for me
finished most of it for maths and fm
just got a module left
Fairs
i dont completely remember, but isnt that something else
Linearization.
im not really too sure but i do remember the thing with the y=mx + c logs thing
Used extensively in chemistry and physics.
make sure its in ur book first
I've heard of it, but I don't know.
Yeah it is
Wait
It’s called reduction to linear form
Is that the same or?
thats the y=mx + c stuff then
Ohh alr
linear programming is somethjng different
Yeah, that's linearization.
if its not in ur book maybe ur doing a diff level or something, im not sure
send a pic of the contents rq? if u dont mind
Alr
Nah.
A lot of stuff is linear, but it's not the same.
Ohh linear inequalities
Yeah everything
thats another way to put it ye
u got that one down?
Can do that on graphing calculator I’m pretty sure
It shows u the region
Then solve for this using g solve function
ur using ur calc to its full potential lmao
i havent heard of any of this but its good to know
Working out marks tho
yk linear programming is a further maths decision alevel topic
idk why its in ocr admaths
its not hard but its boring
Not even in normal a level maths?
polynomial long division yea
u need everything in the book if ur test is on that
pld is easy tho
I’m good at grid method
Yeah it is
normal alevel maths is so dead
boring af
But would questions ask to do it with a certain method?
honestly i only use the long division
Did u have to pick alevel maths to do further maths
its fast and efficient
Oh
Might go over that then asw
Wait, you learn linear programming in school?
ye
Isn't that concerned with minimization of multivariable functions?
just x,y so its not that bad
z gets involved later on too?
Well, still, two variables. Something more like university-level stuff.
no idea
its not too bad honestly
like
we learn the basics
Hm... Well, probably because the functions are linear.
and people who do normal maths never hear of it again lmao
sadly im doing decision maths so i do hear of it again next year
I mean that in general optimization of multivariable functions is a topic in calculus.
And this is constrained optimization, too...
its like graph subgraph group eularian circuit
So, in general, Lagrange multipliers and bordered hessian, which is quite a pain.
probably not something with all those fancy words
its quite simple
at this lvl
cuz its for like
14-15 year olds
or 15-16
prolly 14-15
I see.
Well, it's probably a lot easier, since from what I've seen not only the function is linear, but so are the constraints.
ur fine with kinematics?
@gray stone can u do linear programming on graphing calculator?
variable acceleration
Suvat stuff
As I said, I haven't learned it, so I don't know. I believe it's usually done on a computer.
Might need to revisit that again
rightways is differentiate
Oh alright
integrate is leftways
s= displacement
v= velocity
a=acceleration
down differentiate
up integrate
when acceleration is variable ie the questions are a function in terms of t like “the displacement of a particle is t^2 + t^3 find acceleration”
second derivative of displacement is acceleration yes
And you’d need the differentiate twice here?
yes
u should also know about how to differentiate for the turning point
Turning point?
how to find if a TP is a minimum or a maximum
Make it = 0
I've heard this term before. What does it mean, exactly?
And sub values back in
0,0 for x^2 example
its where the graph turns basically
not a point of inflection
dy/dx = 0
Oh, you mean extremum point?
Hm...
or minimum/maximum
I don't really like that name.
Is this right?
lemme check
Well, critical points are still called critical, right?
wdym by critical
Oh yh forgot to keep the + 2
yep
how do u know if 2+6t is minimum or maximum at t=3?
and then do the same test for -10
Critical points are where the derivative equals zero or doesn't exist. Extremum points are critical points that are either maximum or minimum points.
(replace derivative by gradient for multivariable functions)
Check the y value right
i dont remember the name exactly, cuz we find if its an extreme point or if it inflects
just substitute
Sub back into equation
2+6t at t=3
See which value is lower
Well, the usual process is that you find critical points, then test which ones are extremum points (and what type) and which aren't.
Min or max?
in general
if f’’(t)>0 minimum point
f’’(t)<0 max
If f''(t) exists and not equal to zero, at least.
f’’(t) represents 2nd derivative at the point t=t
ye
in this case check the left and right side
of t
in small intervals
Ibr id just check on graphing calculator
its weird ik but its kinda the opposite
So, for example, f(x) = x^3 (1 - x) has two critical points: x = 0 and x = 3/4. But only x = 3/4 is an extremum point (more specifically, a maximum point), while x = 0 isn't an extremum point.
some graphs get nasty
Or if the function is sufficiently smooth, you can also check higher-order derivatives. Useful for polynomials.
Even in add maths?
ur gonna get stuff to the power of 1/3 and 3/5 etc
not that difficult if u know ur content
but ur wasting time if u plug it into a graphing calculator
without knowing WHY ur doing it
Hmm yeah
graphing calculators i feel like are more of a tool to check ur work
Yeah, true.
ion even use mine apart from when im working with polar curves
Isn’t it easier sometimes to work backwards tho
cuz its useful to understand why an equation outputs said graph
Well, you won't be able to do that on a test 😅
if it works for you, go for it
idk if ur allowed cg50 graphing in admaths
You need to do it by yourself, too.
Wait, calculator? On a math exam?
ye
Huh, that's weird...
Why is that allowed? And how would it help, anyway?
its 1 non-calc 2 calc
ye
Yeah, then it might help. Though, I still find it strange that it's allowed.
I've never seen a calculator allowed on a math exam, and it would be useless in a uni math exam, anyway.
i mean ion think it helps too much but at the same time timed conditions are annoying
Anyway, it's quite late for me now, so let's continue this conversation in the afternoon or evening.
i always find myself with more time than i need though, so maybe no calc is the way to go lmao
okie dokie
@ivory comet binomial distribution
that ones quite easy
When it says atleast one condition
x~B(n,p)
Find probibility atleast one three is rolled
do yk what this means
P is probiliblty of success
last thing before i go im tired
X~B(4 , 1/6)
ye
Alright
so whats the question again lol
Six sided dice
U find p of 0 threes right?
Then do 1 - that
surely u dont need binomial for this
But what do u do after that
Idk how to put it into graphing calcualtor
Lol
Should I take both to exam?
991 and this
It’s like something c domething times p of success ^
ncr * p^r * (1-p)^n-r
Yeah
do u know ur binomial expansion too
Yeah
that ones quite good all sorts of questions come up for that
(x+2/x)^6
find the constant term if one exists
Wait what does r mean again
I just did that exact question
p is probability
n is total trials
r is trials ur looking at
Thanks
160
Yh lol
Crazy
whay about
(x+3/x)^5
find if it exists, if not
if doesnt exist prove why not
prove it doesnt exist
sum from 5 to 0 of x^r * (3/x)^5-r * 5cr
(x^r )( x^r-5) = x*0
2r - 5 = 0
r = 5/2
r has to be a whole number
Huhh
A bit
this is the way i was taught these sorta questions
Not much
write this down
Ok
Yeah
.
alr write that down using the sum formula
the constant term is when x^0 correct?
Yh
because itl have no x
next to it
right, so we want to find the term in our sum when x^0
so ignoring everything else, extract the
x^r * (1/x)^n-r
cuz the nCr and the 3 dont matter
they are constants right
no x term
Yh
ye
Yh
so whats it now
this turns into x^r * (x^r-n)
X^-n-r
are u happy up to here
-(n-r)
Would something like this come up tho?
i did some questions on it ye
its up to u
dependso n ur teachers
ion mind teaching it if u think ur teachers wont put it on the mock
Leave it I think it should be fine
I think I’d be better off learning other stuff rn
defo perms and combs lmao
Thanks tho
ts is so annoying
Tm
Thanks
bye bye
Bye
@halcyon ruin
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