geometry help! | Mathematics | Page 1

sour thunder Feb 23, 2025, 10:14 AM

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in ∆ABC, AD is the median
<ADC is an obtuse angle
AD = 5 cm
BD = 6 CM
area of ∆ABC is 18 cm²
IF ACPQ IS A SQUARE
find area of ADCPQ

dark bobcatBOT Feb 23, 2025, 10:14 AM

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sour thunder in ∆ABC, AD is the median <ADC is an obtuse angle AD = 5 cm BD = 6 CM area of ∆A...

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sour thunder Feb 23, 2025, 10:15 AM

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help

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!help

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!!help

lusty raft Feb 23, 2025, 10:16 AM

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Have you tried making a picture?

sour thunder Feb 23, 2025, 10:16 AM

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no thats the main problem

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i cant even make the picture

lusty raft Feb 23, 2025, 10:17 AM

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Why not?

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You just need a triangle and a median inside of it.

sour thunder Feb 23, 2025, 10:17 AM

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im having problem with the obtuse angle <ADC

lusty raft Feb 23, 2025, 10:18 AM

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Well, you can draw it like this.

sour thunder Feb 23, 2025, 10:21 AM

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hmmmmm

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i was thinking abt something like this

plush dirge Feb 23, 2025, 3:46 PM

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sour thunder in ∆ABC, AD is the median <ADC is an obtuse angle AD = 5 cm BD = 6 CM area of ∆A...

You can use median theorem, Heron's formula, the fact that $AD^2=\frac12AB^2+\frac12AC^2-\frac14BC^2$ by Stewart's Theorem

naive salmonBOT Feb 23, 2025, 3:46 PM

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mathisfun

plush dirge Feb 23, 2025, 3:46 PM

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A lot of things

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$5^2=\frac12AB^2+\frac12AC^2-\frac14\cdot 12^2$

naive salmonBOT Feb 23, 2025, 3:53 PM

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mathisfun

plush dirge Feb 23, 2025, 4:02 PM

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,texsp ||$25+36=\frac12(AB^2+AC^2)$||

naive salmonBOT Feb 23, 2025, 4:02 PM

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mathisfun

plush dirge Feb 23, 2025, 4:03 PM

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,texsp ||$122=AB^2+AC^2$||

naive salmonBOT Feb 23, 2025, 4:04 PM

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mathisfun

plush dirge Feb 23, 2025, 4:04 PM

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$\sqrt{s(s-a)(s-b)(s-c)}=18$

naive salmonBOT Feb 23, 2025, 4:04 PM

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mathisfun

haughty wagonBOT Feb 24, 2025, 5:00 PM

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@sour thunder

<:HelpIcon:1304095958283321385>| Help Reminder

Hello brainrott9_, this is a friendly reminder that your help request has been inactive for more than 24 hours. If you no longer need assistance, please consider closing the thread using the +close command. This thread will be automatically closed in 3 days if it remains inactive.

sour thunder Feb 25, 2025, 5:52 PM

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and?

haughty wagonBOT Feb 25, 2025, 5:52 PM

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@lusty raft The user still needs help with this help request.

sour thunder Feb 25, 2025, 5:55 PM

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plush dirge $\sqrt{s(s-a)(s-b)(s-c)}=18$

go on

sour thunder Feb 25, 2025, 6:16 PM

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can any1 help

lusty raft Feb 25, 2025, 6:33 PM

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sour thunder can any1 help

Try reasoning about the area of the triangle ADC.
Then, you know that AD = 5 cm and CD = BD = 6 cm. So, you'll be able to find the angle ADC.

plush dirge Feb 26, 2025, 12:25 AM

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sour thunder go on

I have different approach now

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Law of cosine on BAC

sour thunder Feb 26, 2025, 9:48 AM

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plush dirge Law of cosine on BAC

its not in our grade

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so dont use trif

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trig

#geometry help!