#How to find a perpendicular line to plane e.g. 2x - y + 5z = 2 passing through given point (1,2,1)?
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parametrise lines passing through that point
then use the fact that it's perpendicular to the plane
you have it written right there in front of you
name a normal vector for the plane and then define a line in the direction of that vector that passes through the given point
if n = (A,B,C) is normal to the plane, then the line is given by nt + (1,2,1), where t in R
so n = (2,-1,5) and (x-1)/2 = (y-2)/-1 = (z-1)/5 ?
that works
@alpine vault
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