initial value problems - differential eq

[high jolt]

can anyone help me see why i got this wrong?

[late shoal]

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[junior zenith]

...how'd you get sqrt(3) = c_1 + c_2?

[high jolt]

by multiplying 2 both sides to cancel out the denominator

[junior zenith]

Denominator of what?

[high jolt]

of sqrt(3)/2 = c1 (1/2) + c2 (sqrt3/2)

[junior zenith]

Uh huh. And multiplying both sides by 2, what do we get?

[high jolt]

OHHH sqrt(3)C2

okay, i got it

thank you

+close

[silver venture]

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[junior zenith]

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