#Proof
1 messages · Page 1 of 1 (latest)
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Tony
We could start with a $x_0 \in M$
Tony
And let $\epsilon>0$
Tony
start with definition of continuity
what do you have to show for f to be continuous?
I have to find a delta>0 s.t $|f(x)-f(x_0)|<\epsilon$
Tony
don't give half assed answers
Kk waitt
Let $\epsilon>0$ and $x_0 \in M$ . We have to find a $\delta>0$ s.t $d_N(f(x),f(x_0))$, with $0<d_M(x,x_0)<\delta$
$d_M(x,x_0)$
Tony
Soryy but pls switch $N$ for $n_0$ since $N$ is already used
Tony
switch it if you want to
Can‘t we just make use of the continuety of $f_n$?
Tony
that's not enough
the convergence is also uniform
you have to make use of both
by continuity you can also say that
$$d(f_{n_0}(x),f_{n_0}(z))\leqslant \frac{\varepsilon}{3}$$
aL
where d(x,z)< delta
Tony
now conclude the result by applying the triangle inequality and you are done
Why epsilon over 3 tho
take epsilon / 11 if you want to
How did u choose it
doesn't matter
Hmm kk
same argument but for a real valued function
adapt to metric space case
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