#Why does taking a convex combination over n co-ordinates result in it being within polygon of n-side

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wispy radish
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Help😅

steady furnaceBOT
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stoic copper
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It is only within if the polygon is convex itself

wispy radish
stoic copper
wispy radish
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Is the inside

stoic copper
wispy radish
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How about "inside is a plane (ABCD) in which every point P that belongs in that plane, has a property that [ABCD]=[PAB]+[PBC]+[PCD]+[PDA]."

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[X] represents that area of shape

wispy radish
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Like sum of the areas of all permutations of x,y of [Pxy] = the whole area of the plane

stoic copper
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Ok so take a polygon. And let’s think of the boundaries (sides). Each side is bounded by 2 vertices right ?

stoic copper
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So basically, the convex combination of the 2 vertices is all the points in between right ?

stoic copper
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Ok so now you see how you can build all the sides just by combinating vertices ?

wispy radish
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Their weights make up 1 already

stoic copper
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Yeah wait for it

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Now take any point from the inside and draw a line (any direction). How many many intersections does the line have with the sides ?

stoic copper
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2 ?

wispy radish
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In all for directions rgiht?

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Ohh 1 linep

wispy radish
stoic copper
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Ok so now these 2 intersections can be combined to find your point inside …

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So basically. You can always boil it down to 2 points

wispy radish
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But what does that mean?

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If you have any paper that proves this convex combination over n- veritces

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Then please let me know

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@stoic copper

stoic copper
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Alright

quiet pilot
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@wispy radish How did INMO go?

wispy radish
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Will not qualify 🫠

wispy radish
wispy radish
quiet pilot
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Did you get any problem correct (even partially)

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P3?

quiet pilot
wispy radish
wispy radish
wispy radish
quiet pilot
quiet pilot
wispy radish
quiet pilot
wispy radish
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My life is fucked. I was in 11th when i gave this year's inmo. So i have got only attempt + (pressure of iit and boards)

quiet pilot
quiet pilot
wispy radish
wispy radish
quiet pilot
quiet pilot
wispy radish
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@stoic copper you there?

pale karmaBOT
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@wispy radish

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